.NET : How to validate XML file with DTD without DOCTYPE declaration

问题

I have an XML file with no DOCTYPE declaration that I would like to validate with an external DTD upon reading.

Dim x_set As Xml.XmlReaderSettings = New Xml.XmlReaderSettings()
x_set.XmlResolver = Nothing
x_set.CheckCharacters = False
x_set.ProhibitDtd = False
x = XmlTextReader.Create(sChemin, x_set)

How do you set the path for that external DTD? How do you validate?

回答1:

I have used the following function successfully before, which should be easy to adapt. How ever this relies on creating a XmlDocument as magnifico mentioned. This can be achieved by:

XmlDocument doc = new XmlDocument();
doc.Load( filename );
doc.InsertBefore( doc.CreateDocumentType( "doc_type_name", null, DtdFilePath, null ), 
    doc.DocumentElement );


/// <summary>
/// Class to test a document against DTD
/// </summary>
/// <param name="doc">XML The document to validate</param>
private static bool ValidateDoc( XmlDocument doc )
{
    bool isXmlValid = true;
    StringBuilder xmlValMsg = new StringBuilder();

    StringWriter sw = new StringWriter();
    doc.Save( sw );
    doc.Save( TestFilename );

    XmlReaderSettings settings = new XmlReaderSettings();
    settings.ProhibitDtd = false;
    settings.ValidationType = ValidationType.DTD;
    settings.ValidationFlags = XmlSchemaValidationFlags.ReportValidationWarnings;
    settings.ValidationEventHandler += new ValidationEventHandler( delegate( object sender, ValidationEventArgs args )
    {
        isXmlValid = false;
        xmlValMsg.AppendLine( args.Message );
    } );

    XmlReader validator = XmlReader.Create( new StringReader( sw.ToString() ), settings );

    while( validator.Read() )
    {
    }
    validator.Close();

    string message = xmlValMsg.ToString();
    return isXmlValid;
}

回答2:

Could you create an Xml.XmlDocument with the DTD you want, then append the XML file data to the in-memory Xml.XmlDocument, then validate that?

回答3:

private static bool _isValid = true;
static void Main(string[] args)
{
    using (MemoryStream ms = new MemoryStream())
    {
        using (FileStream file = new FileStream("C:\\MyFolder\\Product.dtd", FileMode.Open, FileAccess.Read))
        {
            byte[] bytes = new byte[file.Length];
            file.Read(bytes, 0, (int) file.Length);
            ms.Write(bytes, 0, (int) file.Length);
        }
        using (FileStream file = new FileStream("C:\\MyFolder\\Product.xml", FileMode.Open, FileAccess.Read))
        {
            byte[] bytes = new byte[file.Length];
            file.Read(bytes, 0, (int) file.Length);
            ms.Write(bytes, 0, (int) file.Length);
        }
        ms.Position = 0;

        var settings = new XmlReaderSettings();
        settings.DtdProcessing = DtdProcessing.Parse;
        settings.ValidationType = ValidationType.DTD;
        settings.ValidationEventHandler += new ValidationEventHandler(OnValidationEvent);
        var reader = XmlReader.Create(ms, settings);

        // Parse the file.  
        while (reader.Read()) ;
    }
    // Check whether the document is valid or invalid.
    if (_isValid)
        Console.WriteLine("Document is valid");
    else
        Console.WriteLine("Document is invalid");
}

private static void OnValidationEvent(object obj, ValidationEventArgs args)
{
    _isValid = false;
    Console.WriteLine("Validation event\n" + args.Message);
}

来源：https://stackoverflow.com/questions/470313/net-how-to-validate-xml-file-with-dtd-without-doctype-declaration

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.net

xml

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dtd