How to find element by attribute value in GPath?

佐手、 提交于 2019-12-03 22:25:43
Nicolas Modrzyk

Here is the corresponding snippet:

def node = new XmlSlurper().parseText(...)
def foo = node.depthFirst().findAll { it.name() == 'div' && it.@id == 'foo'}

A few other links you may want to read:

The previous poster gave you all that's required: Assuming your document has been slurped into xml, you want

def foo = xml.path.to.div.find{it.@id == 'foo'}

to find a single result. Or findAll to find all results.

To mimic the expression //div[@id='foo'] the closest thing you can do with a GPath is:

def xml = new XmlParser().parseText(text)
xml.'**'.div.findAll { it.@id=="foo" }

the '**' is pretty much the same as '//' in your XPath.

xml.'**'.div

will yield all the nodes of type div at any level.

Later filtering with findAll() with the given closure you get a list of nodes as you do in the XPath case

Grant

what you need is this:

def root = new XmlSlurper().parseText(<locOfXmlFileYouAreParsing>.toURL().text)

def foundNode = root.'**'.find{ it.@id == "foo" }

its the double * that will let you find it without knowing the path. At least this is how I do it.

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