I understand that __dict__
in obj.__dict__
is a descriptor attribute of type(obj)
, so the lookup for obj.__dict__
is type(obj).__dict__['__dict__'].__get__(obj)
.
From https://stackoverflow.com/a/46576009
It's tempting to say that
__dict__
has to be a descriptor because implementing it as a__dict__
entry would require you to find the__dict__
before you can find the__dict__
, but Python already bypasses normal attribute lookup to find__dict__
when looking up other attributes, so that's not quite as compelling as it initially sounds. If the descriptors were replaced with a'__dict__'
key in every__dict__
,__dict__
would still be findable.
How does "Python already bypasses normal attribute lookup to find __dict__
"? What does "normal attribute lookup" mean?
According to the context of the quote in the link, I don't think when the author wrote that, he referred to that the lookup for obj.__dict__
is type(obj).__dict__['__dict__'].__get__(obj)
.
Normal attribute lookup is done by calling the __getattribute__
hook, or more precisely, the C-API tp_getattro
slot. The default implementation for this is in the PyObject_GenericGetAttr
C-API function.
It is the job of PyObject_GenericGetAttr
to invoke descriptors if they exist, and to look at the instance __dict__
. And indeed, there is a __dict__
descriptor, but it is faster for __getattribute__
to just access the __dict__
slot in the instance memory structure directly, and that is what the actual implementation does:
if (dict == NULL) {
/* Inline _PyObject_GetDictPtr */
dictoffset = tp->tp_dictoffset;
if (dictoffset != 0) {
if (dictoffset < 0) {
Py_ssize_t tsize;
size_t size;
tsize = ((PyVarObject *)obj)->ob_size;
if (tsize < 0)
tsize = -tsize;
size = _PyObject_VAR_SIZE(tp, tsize);
assert(size <= PY_SSIZE_T_MAX);
dictoffset += (Py_ssize_t)size;
assert(dictoffset > 0);
assert(dictoffset % SIZEOF_VOID_P == 0);
}
dictptr = (PyObject **) ((char *)obj + dictoffset);
dict = *dictptr;
}
}
Note the Inline _PyObject_GetDictPtr
comment; this is a performance optimisation, as instance attribute lookups are frequent.
If you try to access instance.__dict__
from Python code, then the descriptor is invoked; it is a data descriptor object so is invoked before instance attributes are even looked at.
来源:https://stackoverflow.com/questions/46590843/how-does-python-bypass-normal-attribute-lookup-to-find-dict