C++ Erasing from list of pairs

问题

Very simple: I have the following code and the method erase is not working. I do not see any problem there because if I go to http://www.cplusplus.com/reference/list/list/erase/ , syntax is: iterator erase (iterator position);

list<pair<string,int>> l0 { { "name1", 20 }, { "name2", 30 }, { "name3", 40 } };
for( auto &it : l0 )
    l0 . erase( it );

May there be a problem that there is a list of pair<string,int> and not a list of a basic data types?

EDIT: The problem is that the code is not compilable.

回答1:

The range-for iterates through a container by giving you access to the elements in the container, and not an iterator to an element.

So in for( auto &it : l0 ), it isn't an iterator to a pair but a reference to a pair. This is why your code doesn't compile

This being said, as πάνταῥεῖ pointed out when he initially closed this as a duplicate of Keeping a valid vector::iterator after erase(), even if your code would compile it wouldn't work because of the invalidation of the iterator following the erase:

Iterators, pointers and references referring to elements removed by the function are invalidated. All other iterators, pointers and references keep their validity.

Workaround

You shall not use the range-for, but the traditional for, and iterating using the return value of erase() :

for (auto it=l0.begin(); it!=l0.end(); ) 
    it = l0.erase(it);  // to avoid incrementing an invalidated iterator

Live demo

来源：https://stackoverflow.com/questions/36823150/c-erasing-from-list-of-pairs