问题
I would like to read the actual source code which the linux commands are written with. I've gained some experience using them and now I think it's time to interact with my machine at a deeper level.
I've found some commands here http://directory.fsf.org/wiki/GNU. Unfortunately I wasn't able to find basic commands such as 'ls' which seems to me easy enough to begin.
How exactly do I read the source code of the simple shell commands like 'ls'? I'm running on Ubuntu 12.04
回答1:
All these basic commands are part of the coreutils package.
You can find all information you need here:
http://www.gnu.org/software/coreutils/
If you want to download the latest source, you should use git:
git clone git://git.sv.gnu.org/coreutils
To install git on your Ubuntu machine, you should use apt-get (git is not included in the standard Ubuntu installation):
sudo apt-get install git
Truth to be told, here you can find specific source for the ls command:
http://git.savannah.gnu.org/cgit/coreutils.git/tree/src/ls.c
Only 4984 code lines for a command 'easy enough' as ls... are you still interested in reading it?? Good luck! :D
回答2:
Direct links to source for some popular programs in coreutils:
- cat (767 lines)
- chmod (570 lines)
- cp (2912 lines)
- cut (831 lines)
- date (570 lines)
- df (1718 lines)
- du (1112 lines)
- echo (272 lines)
- head (1070 lines)
- hostname (116 lines)
- kill (312 lines)
- ln (651 lines)
- ls (4954 lines)
- md5sum (878 lines)
- mkdir (306 lines)
- mv (512 lines)
- nice (220 lines)
- pwd (394 lines)
- rm (356 lines)
- rmdir (252 lines)
- shred (1325 lines)
- tail (2301 lines)
- tee (220 lines)
- touch (437 lines)
- wc (801 lines)
- whoami (91 lines)
Full list here.
回答3:
ls is part of coreutils. You can get it with git :
git clone git://git.sv.gnu.org/coreutils
You'll find coreutils listed with other packages (scroll to bottom) on this page.
回答4:
Actually more sane sources are provided by http://suckless.org look at their sbase repository:
git clone git://git.suckless.org/sbase
They are clearer, smarter, simpler and suckless, eg ls.c has just 369 LOC
After that it will be easier to understand more complicated GNU code.
回答5:
CoreUtils referred to in other posts does NOT show the real implementation of most of the functionality which I think you seek. In most cases it provides front-ends for the actual functions that retrieve the data, which can be found here:
It is build upon Gnulib with the actual source code in the lib-subdirectory
回答6:
You can have it on github using the command
git clone https://github.com/coreutils/coreutils.git
You can find all the source codes in the src folder.
You need to have git installed.
Things have changed since 2012, ls source code has now 5309 lines
回答7:
cd ~ && apt-get source coreutils && ls -d coreutils*
You should be able to use a command like this on ubuntu to gather the source for a package, you can omit sudo assuming your downloading to a location you own.
来源：https://stackoverflow.com/questions/11528267/how-do-i-read-the-source-code-of-shell-commands