问题
I have the following code in my AppDelegate
for when my application enters the background:
var backgroundUpdateTask: UIBackgroundTaskIdentifier!
func beginBackgroundUpdateTask() {
self.backgroundUpdateTask = UIApplication.sharedApplication().beginBackgroundTaskWithExpirationHandler({
self.endBackgroundUpdateTask()
})
}
func endBackgroundUpdateTask() {
UIApplication.sharedApplication().endBackgroundTask(self.backgroundUpdateTask)
self.backgroundUpdateTask = UIBackgroundTaskInvalid
}
func doBackgroundTask() {
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), {
self.beginBackgroundUpdateTask()
// Do something with the result.
var timer = NSTimer.scheduledTimerWithTimeInterval(5, target: self, selector: "displayAlert", userInfo: nil, repeats: false)
NSRunLoop.currentRunLoop().addTimer(timer, forMode: NSDefaultRunLoopMode)
NSRunLoop.currentRunLoop().run()
// End the background task.
self.endBackgroundUpdateTask()
})
}
func displayAlert() {
let note = UILocalNotification()
note.alertBody = "As a test I'm hoping this will run in the background every X number of seconds..."
note.soundName = UILocalNotificationDefaultSoundName
UIApplication.sharedApplication().scheduleLocalNotification(note)
}
func applicationDidEnterBackground(application: UIApplication) {
self.doBackgroundTask()
}
I'm hoping that it executes a UILocalNotification()
every X number of seconds specified in the NSTimer.scheduledTimerWithTimeInterval()
however it only executes once.
I'm still trying to get my head around how background tasks work. Is there something I'm missing?
回答1:
In the code sample, the timer you create will only fire once as you have set the "repeats" value to false in the initialiser.
来源:https://stackoverflow.com/questions/28313702/trying-to-implement-beginbackgroundtaskwithexpirationhandler-and-uilocalnotifica