“INSERT INTO …” with SparkSQL HiveContext

问题

I'm trying to run an insert statement with my HiveContext, like this:

hiveContext.sql('insert into my_table (id, score) values (1, 10)')

The 1.5.2 Spark SQL Documentation doesn't explicitly state whether this is supported or not, although it does support "dynamic partition insertion".

This leads to a stack trace like

AnalysisException: 
Unsupported language features in query: insert into my_table (id, score) values (1, 10)
TOK_QUERY 0, 0,20, 0
  TOK_FROM 0, -1,20, 0
    TOK_VIRTUAL_TABLE 0, -1,20, 0
      TOK_VIRTUAL_TABREF 0, -1,-1, 0
        TOK_ANONYMOUS 0, -1,-1, 0
      TOK_VALUES_TABLE 1, 13,20, 41
        TOK_VALUE_ROW 1, 15,20, 41
          1 1, 16,16, 41
          10 1, 19,19, 44
  TOK_INSERT 1, 0,-1, 12
    TOK_INSERT_INTO 1, 0,11, 12
      TOK_TAB 1, 4,4, 12
        TOK_TABNAME 1, 4,4, 12
          my_table 1, 4,4, 12
      TOK_TABCOLNAME 1, 7,10, 22
        id 1, 7,7, 22
        score 1, 10,10, 26
    TOK_SELECT 0, -1,-1, 0
      TOK_SELEXPR 0, -1,-1, 0
        TOK_ALLCOLREF 0, -1,-1, 0

scala.NotImplementedError: No parse rules for:
 TOK_VIRTUAL_TABLE 0, -1,20, 0
  TOK_VIRTUAL_TABREF 0, -1,-1, 0
    TOK_ANONYMOUS 0, -1,-1, 0
  TOK_VALUES_TABLE 1, 13,20, 41
    TOK_VALUE_ROW 1, 15,20, 41
      1 1, 16,16, 41
      10 1, 19,19, 44

Is there any other way to insert to a Hive table that is supported?

回答1:

Data can be appended to a Hive table using the append mode on the DataFrameWriter.

data = hc.sql("select 1 as id, 10 as score")
data.write.mode("append").saveAsTable("my_table")

This gives the same result as an insert.

回答2:

I've had the same problem (Spark 1.5.1), and tried different versions.

Given

sqlContext.sql("create table my_table(id int, score int)")

The only versions that worked looked like this:

sqlContext.sql("insert into table my_table select t.* from (select 1, 10) t")
sqlContext.sql("insert into       my_table select t.* from (select 2, 20) t")

回答3:

The accepted answer saveAsTable fails for me with an AnalysisException (I don't understand why). What works for me instead is:

data = hc.sql("select 1 as id, 10 as score")
data.write.mode("append").insertInto("my_table")

I'm using Spark v2.1.0.

回答4:

You tried to perform something that the data file format cannot, hence the Unsupported language features in query exception.

Many data file format are write-once and no support ACID operation.

Apache ORC supports ACID operation if you need it.

Instead, you can use partition to split your data into folders (/data/year=2017/month=10....), here you can append/insert data into your data lake.

回答5:

try this hiveContext.sql("insert into table my_table select 1, 10") if you haven't change your dynamic partition mode to nonstrict, you have to do this hiveCtx.setConf("hive.exec.dynamic.partition.mode", "nonstrict")

回答6:

When you first time do this

$data.write.mode("append").saveAsTable("my_table")

you should replace "append" with "overwrite", Then, you can use "append".

来源：https://stackoverflow.com/questions/33923348/insert-into-with-sparksql-hivecontext

标签

apache-spark

apache-spark-sql

pyspark

apache-spark-1.5

hivecontext