How to change status of JsonResponse in Django

孤人 提交于 2019-12-03 14:21:11

问题


My API is returning a JSON object on error but the status code is HTTP 200:

response = JsonResponse({'status': 'false', 'message': message})
return response

How can I change the response code to indicate an error?


回答1:


JsonResponse normally returns HTTP 200, which is the status code for 'OK'. In order to indicate an error, you can add an HTTP status code to JsonResponse as it is a subclass of HttpResponse:

response = JsonResponse({'status':'false','message':message}, status=500)



回答2:


Return an actual status

JsonResponse(status=404, data={'status':'false','message':message})



回答3:


To change status code in JsonResponse you can do this :

response = JsonResponse({'status':'false','message':message})
response.status_code = 500
return response



回答4:


Python built-in http library has new class called HTTPStatus which is come from Python 3.5 onward. You can use it when define a status.

from http import HTTPStatus
response = JsonResponse({'status':'false','message':message}, status=HTTPStatus.INTERNAL_SERVER_ERROR)

The value of HTTPStatus.INTERNAL_SERVER_ERROR.value is 500. When someone read your code it's better define someting like HTTPStatus.<STATUS_NAME> other than define an integer value like 500. You can view all the IANA-registered status codes from python library here.




回答5:


This answer from Sayse works but it's undocumented. If you look at the source you find that it passes the remaining **kwargs to the superclass constructor, HttpStatus. However in the docstring they don't mention that. I don't know if it's the convention to assume that keyword args will be passed to the superclass constructor.

You can also use it like this:

JsonResponse({"error": "not found"}, status=404)

I made a wrapper:

from django.http.response import JsonResponse

class JsonResponseWithStatus(JsonResponse):
    """
    A JSON response object with the status as the second argument.

    JsonResponse passes remaining keyword arguments to the constructor of the superclass,
    HttpResponse. It isn't in the docstring but can be seen by looking at the Django
    source.
    """
    def __init__(self, data, status=None, encoder=DjangoJSONEncoder,
                 safe=True, json_dumps_params=None, **kwargs):
        super().__init__(data, encoder, safe, json_dumps_params, status=status, **kwargs)


来源:https://stackoverflow.com/questions/35059916/how-to-change-status-of-jsonresponse-in-django

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!