问题
I want to check when the user double click on applictaion icon that no another instance of this application is already running.
I read about My.Application but i still don't know what to do.
回答1:
The most common pattern for doing this is to use the Singleton pattern. As you haven't indicated a language, I'm going to assume that you are referring to C# here - if not, the principles are still the same in most OO languages.
This article should give you some help.
回答2:
This is something I've used... (C# on .NET 2.0)
[STAThread]
private static void Main(string[] args)
{
//this follows best practices on
//ensuring that this is a single instance app.
string mutexName = "e50cf829-f6b9-471e-8d9f-67eac3699f09";
bool grantedOwnership;
//we prefix the mutexName with "Local\\" to allow this to run under terminal services.
//The "Local\\" prefix forces this into local user space.
//If we want to forbid this in TS, use the "Global\\" prefix.
Mutex singleInstanceMutex = new Mutex(true, "Global\\" + mutexName, out grantedOwnership);
try
{
if (!grantedOwnership)
{
MessageBox.Show("Error: X is already running.\n\nYou can only run one copy of X at a time.", "X", MessageBoxButtons.OK, MessageBoxIcon.Error, MessageBoxDefaultButton.Button1);
Application.Exit();
}
else
{
Application.Run(new X(args));
}
}
finally
{
singleInstanceMutex.Close();
}
}
回答3:
In VB .NET there's a IsSingleInstance boolean property that does the job for you.
In VB (taken from here):
Public Class Program
Inherits Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase
Public Sub New()
Me.IsSingleInstance = True
End Sub
End Class
Here's how you use it in C# (taken from here):
// SingleInstanceApplication.cs
class SingleInstanceApplication : WindowsFormsApplicationBase {
// Must call base constructor to ensure correct initial
// WindowsFormsApplicationBase configuration
public SingleInstanceApplication() {
// This ensures the underlying single-SDI framework is employed,
// and OnStartupNextInstance is fired
this.IsSingleInstance = true;
}
}
// Program.cs
static class Program {
[STAThread]
static void Main(string[] args) {
Application.EnableVisualStyles();
SingleInstanceApplication application =
new SingleInstanceApplication();
application.Run(args);
}
}
Make sure to reference the Microsoft.VisualBasic.dll in your project.
回答4:
Open your Project Properties (Application Tab) and check the Make single instance application option.
From the Application tab, you can also click the View Application Events button, to create an ApplicationEvents.vb class where you can handle the second instance event:
Partial Friend Class MyApplication
Private Sub MyApplication_StartupNextInstance(ByVal sender As Object, ByVal e As Microsoft.VisualBasic.ApplicationServices.StartupNextInstanceEventArgs) Handles Me.StartupNextInstance
' Bring First Instance to Foreground
e.BringToForeground = True
' Pass Second Instance Command Line to First Instance
AppShared.DoSomethingWithCommandLine(e.CommandLine)
End Sub
End Class
回答5:
Scott Hanselman has nice article about this. The code is in C# but I guess it'll be easy to port it to VB.
http://www.hanselman.com/blog/TheWeeklySourceCode31SingleInstanceWinFormsAndMicrosoftVisualBasicdll.aspx
Here's one more article on the topic in case that won't meet your needs:
http://www.codeproject.com/KB/cs/cssingprocess.aspx
回答6:
In VB.NET, a single instance app is just a checkbox on the Project property page. You can also trap the My.Application.StartupNextInstance event to have your single instance do something when another copy is launched. This can be used, for example, for MDI like behavior of opening the requested document in the original instance.
Behind the scenes, this encapsulates a good bit of mutex and IPC goo - see WindowsFormApplicationBase - and can be used from C# as well.
回答7:
Through the tips above, I found out how to make my app a single instance, but I still had to go to another site to find out EXACTLY how. Here is a simple picture how I managed to do that. It was easy-peasy and I hope it helps others with the same need because I'm sure the OP solved this problem 7 years ago:
回答8:
Use Mutex. Effectively, a Mutex can be named with a string, and is unique across the CLR.
Sample code:
try
{
mutex = Mutex.OpenExisting(mutexName);
//since it hasn’t thrown an exception, then we already have one copy of the app open.
MessageBox.Show(”A copy of Todo 3.0 is already open. Please check your system tray (notification area).”,
“Todo 3.0″, MessageBoxButtons.OK, MessageBoxIcon.Information);
Environment.Exit(0);
}
catch (Exception Ex)
{
//since we didn’t find a mutex with that name, create one
Debug.WriteLine(”Exception thrown:” + Ex.Message + ” Creating a new mutex…”);
mutex = new Mutex(true, mutexName);
}
From this post:
回答9:
If your application is in VB.NET 2.0-3.5, the easiest way to keep a single instance of the program running is by using the 'Windows Application Framework Properties'. To get there, right-click on your project name and go to 'Properties'. Once there, select the 'Make single instance appliation' checkbox.
You can also use the ApplicationEvents.vb to show the user that they have run your program a second time. You can create/view that easily in the same properties window by selecting the 'View Application Events' button. Within there, you can select the MyApplication_StartupNextInstance sub and enter in code there, like this:
Private Sub MyApplication_StartupNextInstance(ByVal sender As Object, ByVal e As Microsoft.VisualBasic.ApplicationServices.StartupNextInstanceEventArgs) Handles Me.StartupNextInstance
MessageBox.Show("This program is already running. If you do not see the program running, please check your " _
& "Windows Task Manager for this program name in the 'Processes' Tab." & vbNewLine & vbNewLine & "WARNING: " _
& " If you terminate the process, you will terminate the only instance of this program!", My.Application.Info.ProductName.ToString _
& " is Running!", MessageBoxButtons.OK, MessageBoxIcon.Warning)
End Sub
Let me know if this helps! JFV
回答10:
Assign your app some unique identifier, such as a hardcoded guid and create a Mutex instance where you assign the mutex it that identifier. If it throws an exception then if means your application is already running (as it successfully managed to create the mutex)
回答11:
I thought it would be easier to have the sample right here instead of a link.
[STAThread]
static void Main()
{
if (!IsAppAlreadyRunning())
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1()); /* Change Form1 for your main Form */
}
else
{
MessageBox.Show("Application is already running!");
}
}
public static bool IsAppAlreadyRunning()
{
Process currentProcess = Process.GetCurrentProcess();
return (IsAppAlreadyRunning(currentProcess.Id,
currentProcess.ProcessName));
}
private static bool IsAppAlreadyRunning(int ID, string Name)
{
bool isAlreadyRunning = false;
Process[] processes = Process.GetProcesses();
foreach (Process process in processes)
{
if (ID != process.Id)
{
if (Name == process.ProcessName)
{
isAlreadyRunning = true;
break;
}
}
}
return isAlreadyRunning;
}
来源：https://stackoverflow.com/questions/391339/how-to-make-sure-that-there-is-one-instance-of-the-application-is-running