问题
Unlike other "FRP" libraries, Rx doesn't prevent glitches: callbacks invoked with time-mismatched data. Is there a good way to work around this?
As an example, imagine that we have a series of expensive computations derived from a single stream (e.g. instead of _.identity, below, we do a sort, or an ajax fetch). We do distinctUntilChanged to avoid recomputing the expensive things.
sub = new Rx.Subject();
a = sub.distinctUntilChanged().share();
b = a.select(_.identity).distinctUntilChanged().share();
c = b.select(_.identity).distinctUntilChanged();
d = Rx.Observable.combineLatest(a, b, c, function () { return _.toArray(arguments); });
d.subscribe(console.log.bind(console));
sub.onNext('a');
sub.onNext('b');
The second event will end up causing a number of glitchy states: we get three events out, instead of one, which wastes a bunch of cpu and requires us to explicitly work around the mismatched data.
This particular example can be worked around by dropping the distinctUntilChanged, and writing some wonky scan() functions to pass through the previous result if the input hasn't changed. Then you can zip the results, instead of using combineLatest. It's clumsy, but doable.
However if there is asynchrony anywhere, e.g. an ajax call, then zip doesn't work: the ajax call will complete either synchronously (if cached) or asynchronously, so you can't use zip.
Edit
Trying to clarify the desired behavior with a simpler example:
You have two streams, a and b. b depends on a. b is asynchronous, but the browser may cache it, so it can either update independently of a, or at the same time as a. So, a particular event in the browser can cause one of three things: a updates; b updates; both a and b update. The desired behavior is to have a callback (e.g. render method) invoked exactly once in all three cases.
zip does not work, because when a or b fires alone, we get no callback from zip. combineLatest does not work because when a and b fire together we get two callbacks.
回答1:
The concept
both a and b update
where both a and b are observables, doesn't exist as a primitive in Rx.
There is no lossless, general operator that can be defined to decide when it receives a notification from a whether it should pass it downstream or hold off until it receives a notification from b. Notifications in Rx do not natively carry "both" semantics, or any semantics beyond the Rx Grammar for that matter.
Furthermore, Rx's serial contract prevents an operator from taking advantage of overlapping notifications in an attempt to achieve this goal. (Though I suspect that relying on race conditions isn't your desired approach anyway.)
See §§4.2, 6.7 in the Rx Design Guidelines.
Thus, what I meant above by "There is no lossless, general operator that can be defined..." is that given two observables a and b with independent notifications, any operator that attempts to decide when it receives a notification from a or b whether it must push immediately or wait for the "other" value, must rely on arbitrary timings. It's guesswork. So this hypothetical operator must either drop values (e.g., DistinctUntilChanged or Throttle), or drop time (e.g., Zip or Buffer), though probably some combination of both.
Therefore, if the agent has the ability to push a alone, or b alone, or a and b together as a notification unit, then it's the developer's responsibility to reify this concept of notification unit themselves.
A 3-state type is required: a | b | {a,b}
(Please excuse my lousy JS)
var ab = function(a, b) { this.a = a; this.b = b; }
sub.onNext(new ab('a')); // process a alone
sub.onNext(new ab('a', 'b')); // process a and b together
sub.onNext(new ab(null, 'c')); // process c alone
The shape of the observable's query no longer matters. Observers must be defined to accept this data type. It's the generator's responsibility to apply any necessary buffering or timing calculations based on the semantics of its internal state in order to produce correct notifications for its observers.
By the way, thank you for providing a simple explanation in your edit (it seems clear to me anyway). I had first heard about "glitches" in this Rx forum discussion. As you can see, it was never really concluded. Now I wonder whether that OP's problem was really as simple as this, assuming that I've understood your problem correctly, of course. :-)
Update:
Here's another related discussion, including some more of my thoughts on why Rx is not FRP:
https://social.msdn.microsoft.com/Forums/en-US/bc2c4b71-c97b-428e-ad71-324055a3cd03/another-discussion-on-glitches-and-rx?forum=rx
来源：https://stackoverflow.com/questions/22332407/how-to-avoid-glitches-in-rx