问题
I need to get the length of a .wav file.
Using:
sox output.wav -n stat
Gives:
Samples read: 449718
Length (seconds): 28.107375
Scaled by: 2147483647.0
Maximum amplitude: 0.999969
Minimum amplitude: -0.999969
Midline amplitude: 0.000000
Mean norm: 0.145530
Mean amplitude: 0.000291
RMS amplitude: 0.249847
Maximum delta: 1.316925
Minimum delta: 0.000000
Mean delta: 0.033336
RMS delta: 0.064767
Rough frequency: 660
Volume adjustment: 1.000
How do I use grep or some other method to only output the value of the length in the second column, i.e. 28.107375?
Thanks
回答1:
The stat
effect sends its output to stderr
, use 2>&1
to redirect to stdout
. Use sed
to extract the relevant bits:
sox out.wav -n stat 2>&1 | sed -n 's#^Length (seconds):[^0-9]*\([0-9.]*\)$#\1#p'
回答2:
There is a better way:
soxi -D out.wav
回答3:
This can be done by using:
soxi -D input.mp3
the output will be the duration directly in secondssoxi -d input.mp3
the output will be the duration with the following format hh:mm:ss.ss
回答4:
This worked for me (in Windows):
sox --i -D out.wav
回答5:
I just added an option for JSON output on the 'stat' and 'stats' effects. This should make getting info about an audiofile a little bit easier.
https://github.com/kylophone/SoxJSONStatStats
$ sox somefile.wav -n stat -json
回答6:
There is my solution for C# (unfortunately sox --i -D out.wav
returns wrong result in some cases):
public static double GetAudioDuration(string soxPath, string audioPath)
{
double duration = 0;
var startInfo = new ProcessStartInfo(soxPath,
string.Format("\"{0}\" -n stat", audioPath));
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
startInfo.RedirectStandardError = true;
startInfo.RedirectStandardOutput = true;
var process = Process.Start(startInfo);
process.WaitForExit();
string str;
using (var outputThread = process.StandardError)
str = outputThread.ReadToEnd();
if (string.IsNullOrEmpty(str))
using (var outputThread = process.StandardOutput)
str = outputThread.ReadToEnd();
try
{
string[] lines = str.Split(new string[] { Environment.NewLine }, StringSplitOptions.RemoveEmptyEntries);
string lengthLine = lines.First(line => line.Contains("Length (seconds)"));
duration = double.Parse(lengthLine.Split(':')[1]);
}
catch (Exception ex)
{
}
return duration;
}
回答7:
for ruby:
string = `sox --i -D file_wav 2>&1`
string.strip.to_f
回答8:
In CentOS
sox out.wav -e stat 2>&1 | sed -n 's#^Length (seconds):[^0-9]([0-9.])$#\1#p'
回答9:
sox stat output to array and json encode
$stats_raw = array();
exec('sox file.wav -n stat 2>&1', $stats_raw);
$stats = array();
foreach($stats_raw as $stat) {
$word = explode(':', $stat);
$stats[] = array('name' => trim($word[0]), 'value' => trim($word[1]));
}
echo json_encode($stats);
来源:https://stackoverflow.com/questions/4534372/get-length-of-wav-from-sox-output