How to run every 25 seconds in Quartz scheduler?

*爱你&永不变心* 提交于 2019-12-03 10:19:26

I don't think cron expression will allow you to do that, but you can use

SimpleScheduleBuilder.repeatSecondlyForever( 25 )

as 300 (5 minutes) is a multiple of 25 it will repeat automatically.

If you want a job to trigger at a regular interval then you can use a Quartz SimpleTrigger with a repeatInterval specified.

With Quartz 2.1.5 this will help:

CronTrigger trigger = newTrigger()
    .withIdentity("trigger1", "group1")
    .withSchedule(cronSchedule("0/20 * * * * ?"))
    .build();

The only way to do this with a cron trigger is so complicated as to be useless; you're much better off with the SimpleTrigger from other answers. Nevertheless, if it has to be cron, you need to set up five different cron triggers:

 0/25 0/5 * * * *
15/25 1/5 * * * *
 5/25 2/5 * * * *
20/25 3/5 * * * *
10/25 4/5 * * * *

The first trigger fires at 0:00:25, 0:00:50; then the second trigger fires at 0:01:15 and 0:01:40; the third at 0:02:05, 0:02:30, 0:02:55; the fourth at 0:03:20, 0:03:45; and finally the fifth at 0:04:10 and 0:04:35. The first trigger then takes over again at 0:05:00, etc.

This only works because 25 seconds divides evenly into 5 minutes (which in turn goes evenly into an hour). If you wanted it every 23 seconds? Forget about it!

You can't have a schedule like that for quartz.

One thing you could do is schedule a wrapper job to run every 5 seconds, and only do any work every fifth execution.

You could schedule the job to run constantly but throttle the frequency using Camel's Throttler.

<route>
  <from uri="jms:queue:TestQueue"/>
  <!-- throttle 1 messages per 25 sec -->
  <throttle timePeriodMillis="25000">
    <constant>1</constant>
    <to uri="bean:TestBean?method=testMethod"/>
  </throttle>
</route>
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