How to generate “screenshot” of html div with external images?

问题

I have a HTML div with external images. (The following is an example, but in the actual case I am using Amazon S3, so downloading and storing the image on the same server is not an option) Currently I am using html2canvas to convert the div to image. However, the external image is always replaced by a blank space.

The code I use to capture the image:

$(function() { 
    $("#btnSave").click(function() { 
        html2canvas($("#widget"), {
            onrendered: function(canvas) {
                theCanvas = canvas;
                document.body.appendChild(canvas);

                // Convert and download as image 
                Canvas2Image.saveAsPNG(canvas); 
                $("#img-out").append(canvas);
            }
        });
    });
});

Edited: jsfiddle: https://jsfiddle.net/0y2zxxL8/3/

I may use other library. I may also do that in backend. (I am using PHP + laravel 5 for backend) Is there a way I can generate a "screenshot" of the HTML div with external images?

Update The current answer are working after editing. Yet, for my actual use, there will be multiple image with their position set by the user by drag and drop. I can still get the position, but it would be better for me if it is possible to not set the position specifically.

回答1:

Your JSFiddle given ReferenceError: Canvas2Image is not defined while hit on 'Save PNG' button. So check your code(not fiddle) for same error.

UPDATE
See this JSFiddle example as reference. May this one will help you.

UPDATE 2
I place some code into your one, check it out. Hope this will be your solution..!

Working result with FF v44 and its working. Taken snap with JSFiddle code

$(function() { 
    $("#btnSave").click(function() { 
        html2canvas($("#widget"), {
            onrendered: function(canvas) {
                var context=canvas.getContext("2d"); // returns the 2d context object
                var img=new Image() //creates a variable for a new image

                img.src= "http://lorempixel.com/400/200/"; // specifies the location of the image
                context.drawImage(img,0,50); // draws the image at the specified x and y location
                // Convert and download as image 
                theCanvas = canvas;
                document.body.appendChild(canvas);

                // Convert and download as image 
                Canvas2Image.saveAsPNG(canvas); 
                $("#img-out").append(canvas);
            }
        });
    });
});

UPDATE 3 (12/29/2016) JSFiddle

After research, found that the problem is because we are only assigning the image source which is only pass message to the browser to retrieve the data.

Further image element is may be not really accessible with the browser when click to draw canvas from it. We are just tell code to load it and it's done.

Change code to solve OP's facing chrome issue like below:

img.onload = function() {
  context.drawImage(img, 0, 50);// draws the image at the specified x and y location
}

UPDATE 4 JSFiddle
Make image position dynamic based on OP requirement.

回答2:

You may try to scan the image source for external urls and change them to your website and load them with php.

Something like

$(function() { 

  var imageproxy = "http://example.com/imageproxy.php"; //Change this
  var mydomain = new RegExp(location.host);

  $("#btnSave").click(function() { 

    $("#widget").find('img').each(function(){

       var img_src = $(this).attr('src');
       if(!mydomain.test(img_src)){
           $(this).attr('src', imageproxy + "?url=" + encodeURIComponent(img_src));
       }
    });

    html2canvas($("#widget"), {
        onrendered: function(canvas) {

            var link = $('<a target="_blank">Download</a>');
            link.attr('download', 'test.png');
            link.attr('href', canvas.toDataURL());

            $("#btnSave").after(link);
        }
    });
  });
});

imageproxy.php

<?php

if(!empty($_GET['url'])){

    $url = urldecode($_GET['url']);
    $img_type = "image/jpeg";

    $chunks = explode('.', $url);

    if(is_array($chunks) && count($chunks) > 1){
        $ext = end($chunks);

        switch ($ext){

            case 'jpg':
            case 'jpeg':
                $img_type = "image/jpeg";
            break;

            case 'png':
                $img_type = "image/png";
            break;

            case 'gif':
                $img_type = "image/gif";
            break;
        }
    }


    $img = file_get_contents($url);

    header ("Content-Type: $img_type");
    echo $img;
}

note: php script is very simple, image detection is not working 100%, this is just ti give you an idea. If you use some php image libs to load and get image type you can do this just with few lines of code. you may also try with "php readfile".

回答3:

onrendered is no longer working..

i solved this problem by adding "allowTaint" option

{ allowTaint: true }

2018 solution:

html2canvas(document.getElementById('result'), { allowTaint: true }).then(function (canvas) {
    document.body.appendChild(canvas);
});

来源：https://stackoverflow.com/questions/41254805/how-to-generate-screenshot-of-html-div-with-external-images

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javascript

php

html

laravel

html2canvas