How do I break out of a loop in Perl?

问题

I'm trying to use a break statement in a for loop, but since I'm also using strict subs in my Perl code, I'm getting an error saying:

Bareword "break" not allowed while "strict subs" in use at ./final.pl line 154.

Is there a workaround for this (besides disabling strict subs)?

My code is formatted as follows:

for my $entry (@array){
    if ($string eq "text"){
         break;
    }
}

回答1:

Oh, I found it. You use last instead of break

for my $entry (@array){
    if ($string eq "text"){
         last;
    }
}

回答2:

Additional data (in case you have more questions):

FOO: {
       for my $i ( @listone ){
          for my $j ( @listtwo ){
                 if ( cond( $i,$j ) ){

                    last FOO;  # --->
                                   # |
                 }                 # |
          }                        # |
       }                           # |
 } # <-------------------------------

回答3:

Simply last would work here:

for my $entry (@array){
    if ($string eq "text"){
         last;
    }
}

If you have nested loops, then last will exit from the innermost. Use labels in this case:

LBL_SCORE: {
       for my $entry1 ( @array1 ){
          for my $entry2 ( @array2 ){
                 if ( $entry1 eq $entry2 ){   # or any condition
                    last LBL_SCORE;
                 }
          }
       }
 }

Given last statement will make compiler to come out from both the loops. Same can be done in any number of loops, and labels can be fixed anywhere.

回答4:

On a large iteration I like using interrupts. Just press Ctrl + C to quit:

my $exitflag = 0;
$SIG{INT} = sub { $exitflag=1 };

while(!$exitflag) {
    # Do your stuff
}

来源：https://stackoverflow.com/questions/303216/how-do-i-break-out-of-a-loop-in-perl