问题
I have a regular expression which I want to negate, e.g.
/(.{0,4})
which String.matches returns the following
"/1234" true
"/12" true
"/" true
"" false
"1234" false
"/12345" false
Is there a way to negate (using regx only) to the above so that the results are:
"/1234" false
"/12" false
"/" false
"" true
"1234" true
"/12345" true
I'm looking for a general solution that would work for any regx without re-writing the whole regex.
I have looked at the following How to negate the whole regex? using (?! pattern), but that doesn't seem to work for me.
The following regx
(?!/(.{0,4}))
returns the following:
"/1234" false
"/12" false
"/" false
"" true
"1234" false
"/12345" false
which is not what I want. Any help would be appreciated.
回答1:
You need to add anchors. The original regex (minus the unneeded parentheses):
/.{0,4}
...matches a string that contains a slash followed by zero to four more characters. But, because you're using the matches() method it's automatically anchored, as if it were really:
^/.{0,4}$
To achieve the inverse of that, you can't rely on automatic anchoring; you have to make at least the end anchor explicit within the lookahead. You also have to "pad" the regex with a .* because matches() requires the regex to consume the whole string:
(?!/.{0,4}$).*
But I recommend that you explicitly anchor the whole regex, like so:
^(?!/.{0,4}$).*$
It does no harm, and it makes your intention perfectly clear, especially to people who learned regexes from other flavors like Perl or JavaScript. The automatic anchoring of the matches() method is highly unusual.
来源：https://stackoverflow.com/questions/8610743/how-to-negate-any-regular-expression-in-java