问题
This question already addresses how to remove duplicate lines, but enforces that the list is sorted first.
I would like to perform the remove contiguous duplicate lines step (i.e. uniq) without first sorting them.
Example before:
Foo
Foo
Bar
Bar
Example after:
Foo
Bar
回答1:
Just found the solution here. The following regex works correctly:
g/^\(.*\)$\n\1$/d
回答2:
:%!uniq
if you're on a unix system, or a system that has the uniq program
回答3:
If you want to remove non-contiguous duplicates you could use
:g/^\(.*\)\ze\n\%(.*\n\)*\1$/d
(which will remove all but the last copy of a line)
which would change
Foo
Bar
Foo
Bar
Foo
Baz
Foo
Quux
to
Bar
Baz
Foo
Quux
If you want to remove all but the first copy, try
:g/^/m0
:g/^\(.*\)\ze\n\%(.*\n\)*\1$/d
:g/^/m0
which would change
Foo
Bar
Foo
Bar
Foo
Baz
Foo
Quux
to
Foo
Bar
Baz
Quux
回答4:
If you just want to remove contiguous duplicate lines, just use uniq without sorting anything.
:%!uniq
回答5:
:%s/^\(.*\)\(\n\1\)\+$/\1/ge
this is my answer for you
回答6:
I know this is old, but it's worth mentioning the following also works if you don't mind sorting as well (I know the OP wanted to avoid it):
:sort u
来源：https://stackoverflow.com/questions/2738826/removing-contiguous-duplicate-lines-in-vi-without-sorting