Using Stride in Swift 2.0

问题

I'm trying to figure out how to use the Stride features in Swift.

It seems to have changed again, since Xcode 7.0 beta 6.

Previously I could use

let strideAmount = stride(from: 0, to: items.count, by: splitSize)
let sets = strideAmount.map({ clients[$0..<advance($0, splitSize, items.count)] })

Now, despite the code hint I cannot figure out how to use this feature.

Any examples would be helpful thanks.

I've looked at examples, but I cannot come to grips with how to use it. All I get from the Apple Docs are limited.

Thanks

回答1:

It changed a bit, here is the new syntax:

0.stride(to: 10, by: 2)

and

Array(0.stride(to: 10, by: 2)) // is [0, 2, 4, 6, 8]

if you take a look at here, you can see what types conform to the Strideable protocol.

As @RichFox pointed out, in Swift 3.0 the syntax changed back to the original global function form like:

stride(from:0, to: 10, by: 2)

回答2:

Usage of stride function in swift 4.2

12345
 2345
  345
   45
    5
    5
   45
  345
 2345
12345


for i in 1...5{
    for k in 1...i{
        print(terminator : " ")
    }
    for j in stride(from: i, to: 6, by: 1){
        print(j , terminator : "")
    }

    print(" ")
}
for i in stride(from: 5, to: 0, by: -1)
{
    for k in 1...i{
        print(terminator : " ")
    }
    for j in stride(from: i, to: 6, by: 1){
        print(j,terminator : "")
    }
    print(" ")
}
1 2 3 4 5
 2 3 4 5
  3 4 5
   4 5
    5
    5
   4 5
  3 4 5
 2 3 4 5
1 2 3 4 5
for i in 1...5{
    for k in 0...i{
        print(terminator : " ")
    }
    for j in stride(from: i, to: 6, by: 1){
        print(j , terminator : " ")
    }

    print(" ")
}

for i in stride(from: 6, to: 1, by: -1){
    for k in 1...i{
        print(terminator : " ")
    }
    for j in stride(from: i-1, to: 6, by: 1){
        print(j , terminator : " ")
    }

    print(" ")
}

来源：https://stackoverflow.com/questions/32197250/using-stride-in-swift-2-0

标签

swift

Sequence

stride