问题
I'm struggling with mongoengine syntax.
I have the following models...
class Post(EmbeddedDocument):
uid = StringField(required=True)
text = StringField(required=True)
when = DateTimeField(required=True)
class Feed(Document):
label = StringField(required=True)
feed_url = StringField(required=True)
posts = ListField(EmbeddedDocumentField(Post))
def my_method(self, post):
pass
... and with the post object passed into to my_method, I'd like to update an existing post if it exists in self.posts with a matching uid, or push to self.posts if not.
Is there syntax to do that in one call in mongoengine?
回答1:
No with list field you cannot do an upsert into a list in a single query. $addToSet
wont work as you've changed the post
so you cant match. You can code round this but it does create a race condition where there is a small window of opportunity for error eg:
class Post(EmbeddedDocument):
uid = StringField(required=True)
text = StringField(required=True)
class Feed(Document):
label = StringField(required=True)
feed_url = StringField(required=True)
posts = ListField(EmbeddedDocumentField(Post))
Feed.drop_collection()
Feed(
label="label",
feed_url="www.feed.com"
).save()
post = Post(uid='1', text="hi")
updated = Feed.objects(posts__uid=post.uid).update_one(set__posts__S=post)
if not updated:
Feed.objects.update_one(push__posts=post)
First we try to update and if it doesn't exist we push to the list - this is where there is a window of opportunity for another process to run and potentially push the post
on the list.
The risk might be acceptable but realistically, I think changing your schema is better, potentially splitting Post
out into its own collection. Then you can use an update statement and set the whole object. The cost will be an extra query to get the feed data.
回答2:
Feed.objects.filter(posts__uid=post.uid).\
update_one(push__posts__S__comments='comment demo')
来源:https://stackoverflow.com/questions/12387478/updating-a-list-of-embedded-documents-in-mongoengine