C++ define class member struct and return it in a member function

末鹿安然 提交于 2019-12-03 06:29:17

You need to change the order of the members of UserInformation and put struct UserInfo above the declaration of getInfo. The compiler complains that it can't work out the signature for getInfo because it hasn't seen the definition of its return type yet.

Also, if you are returning a struct from the function the type of the struct must be visible to the callers. So you need to make the struct public as well.

It makes sense to make the nested structure type public, since the user code should be able to use it. Also, place the declaration of the structure before the point of its first use. Outside the class scope use scope resolution :: to refer to nested types.

class UserInformation
{
public:
    struct UserInfo
    {
        int repu, quesCount, ansCount;
    };


public:
    UserInfo getInfo(int userId);

private:
    UserInfo infoStruct;
    int date;
};

UserInformation::UserInfo UserInformation::getInfo(int userId)
{
    infoStruct.repu = 1000;
    return infoStruct;
}

If the member function is public, then the return type must be publicly visible! Therefore, move the inner struct definition into the public section.

Note also that it must be defined before the function that uses it.

Just do UserInformation::userInfo UserInformation::getInfo(int userId).

Also, you should declare userInfo public.

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!