EDIT: Wrapped the example map in a code block so the formatting is correct.
Ok, I'm trying to write an extremely simple A* algorithm over a hexagonal grid. I understand, and can do the A* portion. In fact, my A* works for square grids. What I can't wrap my brain around is finding neighbors with hexagons. Here's the layout for the heagonal grid
0101 0301
0201 0401
0102 0302
0202 0402
etc, etc
So, what I need help with is writing a Hexagon class that, given it's hex coordinates, can generate a list of neighbors. It needs to be able to generate neighbors which would 'fall off' the grid (like 0000 or 2101 in a 20x20 grid) because that's how my A* tracks across multiple maps laid side-by-side. So something that would work with this code snippet:
planet = Hex('0214') print(planet.neighbors()) ['Hex 0213', 'Hex 0215', 'Hex 0115', 'Hex 0315', 'Hex 0116', 'Hex 0316']
It depends on how you define the coordinates of your hex tiles.
Let's see.
, , , ,
/ \ / \ / \ / \
| A1| A2| A3| A4|
\ / \ / \ / \ /
| B1| B2| B3|
/ \ / \ / \ / \
| C1| C2| C3| C4|
\ / \ / \ / \ /
' ' ' '
In this case, neighbor definition is different for even and odd rows.
For a cell (X,Y) where Y is even, the neighbors are: (X,Y-1),(X+1,Y-1),(X-1,Y),(X+1,Y),(X,Y+1),(X+1,Y+1)
For a cell (X,Y) where Y is odd, the neighbors are: (X-1,Y-1),(X,Y-1),(X-1,Y),(X+1,Y),(X-1,Y+1),(X,Y+1)
Per my comment above, here is the code I implemented. Anybody with suggestions to help me clean it up, I'd welcome the feedback.
class Hexagon():
"""Implements a class of hexagon from a hex map which is vertically tiled.
This hexagon is able to return a list of it's neighbors. It does not care
if the neighbors are hexes which actually exist on the map or not, the map is
responsible for determining that."""
def __init__(self,grid_number):
self.name = grid_number
self.x = int(grid_number[0:2])
self.y = int(grid_number[2:4])
def neighbors(self):
ret_list = []
if self.x % 2 == 0:
temp_list = [[self.x,self.y-1],
[self.x-1,self.y], [self.x+1,self.y],
[self.x-1,self.y+1],[self.x+1,self.y+1],
[self.x,self.y+1]]
for i in temp_list:
ret_list.append(format(i[0],'02d') + format(i[1],'02d'))
elif self.x % 2 == 1:
temp_list = [[self.x,self.y-1],
[self.x-1,self.y-1],[self.x+1,self.y-1],
[self.x-1,self.y],[self.x+1,self.y],
[self.x,self.y+1]]
for i in temp_list:
ret_list.append(format(i[0],'02d') + format(i[1],'02d'))
return ret_list
def main():
hex1 = Hexagon('0201')
hex2 = Hexagon('0302')
if hex1.neighbors() == ['0200','0101','0301','0102','0302','0202']:
print("Works for even columns.")
else:
print("Failed for even columns.")
print(hex1.neighbors())
if hex2.neighbors() == ['0301','0201','0401','0202','0402','0303']:
print("Works for odd columns.")
else:
print("Failed for odd columns.")
print(hex2.neighbors())
if __name__ == '__main__':
main()
来源:https://stackoverflow.com/questions/6661169/finding-adjacent-neighbors-on-a-hexagonal-grid