问题
Simple question for which I could not find answer on the net. In variadic argument macros, how to find the number of arguments? I am okay with boost preprocessor, if it has the solution.
If it makes a difference, I am trying to convert variable number of macro arguments to boost preprocessor sequence, list, or array for further reprocessing.
回答1:
This is actually compiler dependent, and not supported by any standard.
Here however you have a macro implementation that does the count:
#define PP_NARG(...) \
PP_NARG_(__VA_ARGS__,PP_RSEQ_N())
#define PP_NARG_(...) \
PP_ARG_N(__VA_ARGS__)
#define PP_ARG_N( \
_1, _2, _3, _4, _5, _6, _7, _8, _9,_10, \
_11,_12,_13,_14,_15,_16,_17,_18,_19,_20, \
_21,_22,_23,_24,_25,_26,_27,_28,_29,_30, \
_31,_32,_33,_34,_35,_36,_37,_38,_39,_40, \
_41,_42,_43,_44,_45,_46,_47,_48,_49,_50, \
_51,_52,_53,_54,_55,_56,_57,_58,_59,_60, \
_61,_62,_63,N,...) N
#define PP_RSEQ_N() \
63,62,61,60, \
59,58,57,56,55,54,53,52,51,50, \
49,48,47,46,45,44,43,42,41,40, \
39,38,37,36,35,34,33,32,31,30, \
29,28,27,26,25,24,23,22,21,20, \
19,18,17,16,15,14,13,12,11,10, \
9,8,7,6,5,4,3,2,1,0
/* Some test cases */
PP_NARG(A) -> 1
PP_NARG(A,B) -> 2
PP_NARG(A,B,C) -> 3
PP_NARG(A,B,C,D) -> 4
PP_NARG(A,B,C,D,E) -> 5
PP_NARG(1,2,3,4,5,6,7,8,9,0,
1,2,3,4,5,6,7,8,9,0,
1,2,3,4,5,6,7,8,9,0,
1,2,3,4,5,6,7,8,9,0,
1,2,3,4,5,6,7,8,9,0,
1,2,3,4,5,6,7,8,9,0,
1,2,3) -> 63
回答2:
I usually use this macro to find a number of params:
#define NUMARGS(...) (sizeof((int[]){__VA_ARGS__})/sizeof(int))
Full example:
#include <stdio.h>
#include <string.h>
#include <stdarg.h>
#define NUMARGS(...) (sizeof((int[]){__VA_ARGS__})/sizeof(int))
#define SUM(...) (sum(NUMARGS(__VA_ARGS__), __VA_ARGS__))
void sum(int numargs, ...);
int main(int argc, char *argv[]) {
SUM(1);
SUM(1, 2);
SUM(1, 2, 3);
SUM(1, 2, 3, 4);
return 1;
}
void sum(int numargs, ...) {
int total = 0;
va_list ap;
printf("sum() called with %d params:", numargs);
va_start(ap, numargs);
while (numargs--)
total += va_arg(ap, int);
va_end(ap);
printf(" %d\n", total);
return;
}
It is completely valid C99 code. It has one drawback, though - you cannot invoke the macro SUM() without params, but GCC has a solution to it - see here.
So in case of GCC you need to define macros like this:
#define NUMARGS(...) (sizeof((int[]){0, ##__VA_ARGS__})/sizeof(int)-1)
#define SUM(...) sum(NUMARGS(__VA_ARGS__), ##__VA_ARGS__)
and it will work even with empty parameter list
回答3:
If you are using C++11, and you need the value as a C++ compile-time constant, a very elegant solution is this:
#include <tuple>
#define MACRO(...) \
std::cout << "num args: " \
<< std::tuple_size<decltype(std::make_tuple(__VA_ARGS__))>::value \
<< std::endl;
Please note: the counting happens entirely at compile time, and the value can be used whenever compile-time integer is required, for instance as a template parameter to std::array.
回答4:
For convenience, here's an implementation that works for 0 to 70 arguments, and works in Visual Studio, GCC, and Clang. I believe it will work in Visual Studio 2010 and later, but have only tested it in VS2013.
#ifdef _MSC_VER // Microsoft compilers
# define GET_ARG_COUNT(...) INTERNAL_EXPAND_ARGS_PRIVATE(INTERNAL_ARGS_AUGMENTER(__VA_ARGS__))
# define INTERNAL_ARGS_AUGMENTER(...) unused, __VA_ARGS__
# define INTERNAL_EXPAND(x) x
# define INTERNAL_EXPAND_ARGS_PRIVATE(...) INTERNAL_EXPAND(INTERNAL_GET_ARG_COUNT_PRIVATE(__VA_ARGS__, 69, 68, 67, 66, 65, 64, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49, 48, 47, 46, 45, 44, 43, 42, 41, 40, 39, 38, 37, 36, 35, 34, 33, 32, 31, 30, 29, 28, 27, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0))
# define INTERNAL_GET_ARG_COUNT_PRIVATE(_1_, _2_, _3_, _4_, _5_, _6_, _7_, _8_, _9_, _10_, _11_, _12_, _13_, _14_, _15_, _16_, _17_, _18_, _19_, _20_, _21_, _22_, _23_, _24_, _25_, _26_, _27_, _28_, _29_, _30_, _31_, _32_, _33_, _34_, _35_, _36, _37, _38, _39, _40, _41, _42, _43, _44, _45, _46, _47, _48, _49, _50, _51, _52, _53, _54, _55, _56, _57, _58, _59, _60, _61, _62, _63, _64, _65, _66, _67, _68, _69, _70, count, ...) count
#else // Non-Microsoft compilers
# define GET_ARG_COUNT(...) INTERNAL_GET_ARG_COUNT_PRIVATE(0, ## __VA_ARGS__, 70, 69, 68, 67, 66, 65, 64, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49, 48, 47, 46, 45, 44, 43, 42, 41, 40, 39, 38, 37, 36, 35, 34, 33, 32, 31, 30, 29, 28, 27, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0)
# define INTERNAL_GET_ARG_COUNT_PRIVATE(_0, _1_, _2_, _3_, _4_, _5_, _6_, _7_, _8_, _9_, _10_, _11_, _12_, _13_, _14_, _15_, _16_, _17_, _18_, _19_, _20_, _21_, _22_, _23_, _24_, _25_, _26_, _27_, _28_, _29_, _30_, _31_, _32_, _33_, _34_, _35_, _36, _37, _38, _39, _40, _41, _42, _43, _44, _45, _46, _47, _48, _49, _50, _51, _52, _53, _54, _55, _56, _57, _58, _59, _60, _61, _62, _63, _64, _65, _66, _67, _68, _69, _70, count, ...) count
#endif
static_assert(GET_ARG_COUNT() == 0, "GET_ARG_COUNT() failed for 0 arguments");
static_assert(GET_ARG_COUNT(1) == 1, "GET_ARG_COUNT() failed for 1 argument");
static_assert(GET_ARG_COUNT(1,2) == 2, "GET_ARG_COUNT() failed for 2 arguments");
static_assert(GET_ARG_COUNT(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70) == 70, "GET_ARG_COUNT() failed for 70 arguments");
回答5:
There are some C++11 solutions for finding the number of arguments at compile-time, but I'm surprised to see that no one has suggested anything so simple as:
#define VA_COUNT(...) detail::va_count(__VA_ARGS__)
namespace detail
{
template<typename ...Args>
constexpr std::size_t va_count(Args&&...) { return sizeof...(Args); }
}
This doesn't require inclusion of the <tuple> header either.
回答6:
With msvc extension:
#define Y_TUPLE_SIZE(...) Y_TUPLE_SIZE_II((Y_TUPLE_SIZE_PREFIX_ ## __VA_ARGS__ ## _Y_TUPLE_SIZE_POSTFIX,32,31,30,29,28,27,26,25,24,23,22,21,20,19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0))
#define Y_TUPLE_SIZE_II(__args) Y_TUPLE_SIZE_I __args
#define Y_TUPLE_SIZE_PREFIX__Y_TUPLE_SIZE_POSTFIX ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,0
#define Y_TUPLE_SIZE_I(__p0,__p1,__p2,__p3,__p4,__p5,__p6,__p7,__p8,__p9,__p10,__p11,__p12,__p13,__p14,__p15,__p16,__p17,__p18,__p19,__p20,__p21,__p22,__p23,__p24,__p25,__p26,__p27,__p28,__p29,__p30,__p31,__n,...) __n
Works for 0 - 32 arguments. This limit can be easily extended.
回答7:
this works with 0 arguments with gcc/llvm. [links are dumb]
/*
* we need a comma at the start for ##_VA_ARGS__ to consume then
* the arguments are pushed out in such a way that 'cnt' ends up with
* the right count.
*/
#define COUNT_ARGS(...) COUNT_ARGS_(,##__VA_ARGS__,6,5,4,3,2,1,0)
#define COUNT_ARGS_(z,a,b,c,d,e,f,cnt,...) cnt
#define C_ASSERT(test) \
switch(0) {\
case 0:\
case test:;\
}
int main() {
C_ASSERT(0 == COUNT_ARGS());
C_ASSERT(1 == COUNT_ARGS(a));
C_ASSERT(2 == COUNT_ARGS(a,b));
C_ASSERT(3 == COUNT_ARGS(a,b,c));
C_ASSERT(4 == COUNT_ARGS(a,b,c,d));
C_ASSERT(5 == COUNT_ARGS(a,b,c,d,e));
C_ASSERT(6 == COUNT_ARGS(a,b,c,d,e,f));
return 0;
}
Visual Studio seems to be ignoring the ## operator used to consume the empty argument. You can probably get around that with something like
#define CNT_ COUNT_ARGS
#define PASTE(x,y) PASTE_(x,y)
#define PASTE_(x,y) x ## y
#define CNT(...) PASTE(ARGVS,PASTE(CNT_(__VA_ARGS__),CNT_(1,##__VA_ARGS__)))
//you know its 0 if its 11 or 01
#define ARGVS11 0
#define ARGVS01 0
#define ARGVS12 1
#define ARGVS23 2
#define ARGVS34 3
回答8:
herein a simple way to count 0 or more arguments of VA_ARGS, my exemple assumes a maximum of 5 variables, but you can add more if you want.
#define VA_ARGS_NUM_PRIV(P1, P2, P3, P4, P5, P6, Pn, ...) Pn
#define VA_ARGS_NUM(...) VA_ARGS_NUM_PRIV(-1, ##__VA_ARGS__, 5, 4, 3, 2, 1, 0)
VA_ARGS_NUM() ==> 0
VA_ARGS_NUM(19) ==> 1
VA_ARGS_NUM(9, 10) ==> 2
...
回答9:
I'm assuming that each argument to VA_ARGS will be comma separated. If so I think this should work as a pretty clean way to do this.
#include <cstring>
constexpr int CountOccurances(const char* str, char c) {
return str[0] == char(0) ? 0 : (str[0] == c) + CountOccurances(str+1, c);
}
#define NUMARGS(...) (CountOccurances(#__VA_ARGS__, ',') + 1)
int main(){
static_assert(NUMARGS(hello, world) == 2, ":(") ;
return 0;
}
Worked for me on godbolt for clang 4 and GCC 5.1. This will compute at compile time, but won't evaluate for the preprocessor. So if you are trying to do something like making a FOR_EACH, then this won't work.
回答10:
You can stringfy and count tokens:
int countArgs(char *args)
{
int result = 0;
int i = 0;
while(isspace(args[i])) ++i;
if(args[i]) ++result;
while(args[i]) {
if(args[i]==',') ++result;
else if(args[i]=='\'') i+=2;
else if(args[i]=='\"') {
while(args[i]) {
if(args[i+1]=='\"' && args[i]!='\\') {
++i;
break;
}
++i;
}
}
++i;
}
return result;
}
#define MACRO(...) \
{ \
int count = countArgs(#__VA_ARGS__); \
printf("NUM ARGS: %d\n",count); \
}
回答11:
Boost Preprocessor actually has this as of Boost 1.49, as BOOST_PP_VARIADIC_SIZE(...). It works up to size 64.
Under the hood, it's basically the same as Kornel Kisielewicz's answer.
来源：https://stackoverflow.com/questions/2124339/c-preprocessor-va-args-number-of-arguments