问题
I'm trying to wrap my head around shaders in GLSL, and I've found some useful resources and tutorials, but I keep running into a wall for something that ought to be fundamental and trivial: how does my fragment shader retrieve the color of the current fragment?
You set the final color by saying gl_FragColor = whatever, but apparently that's an output-only value. How do you get the original color of the input so you can perform calculations on it? That's got to be in a variable somewhere, but if anyone out there knows its name, they don't seem to have recorded it in any tutorial or documentation that I've run across so far, and it's driving me up the wall.
回答1:
The fragment shader receives gl_Color and gl_SecondaryColor as vertex attributes. It also gets four varying variables: gl_FrontColor, gl_FrontSecondaryColor, gl_BackColor, and gl_BackSecondaryColor that it can write values to. If you want to pass the original colors straight through, you'd do something like:
gl_FrontColor = gl_Color;
gl_FrontSecondaryColor = gl_SecondaryColor;
gl_BackColor = gl_Color;
gl_BackSecondaryColor = gl_SecondaryColor;
Fixed functionality in the pipeline following the vertex shader will then clamp these to the range [0..1], and figure out whether the vertex is front-facing or back-facing. It will then interpolate the chosen (front or back) color like usual. The fragment shader will then receive the chosen, clamped, interpolated colors as gl_Color and gl_SecondaryColor.
For example, if you drew the standard "death triangle" like:
glBegin(GL_TRIANGLES);
glColor3f(0.0f, 0.0f, 1.0f);
glVertex3f(-1.0f, 0.0f, -1.0f);
glColor3f(0.0f, 1.0f, 0.0f);
glVertex3f(1.0f, 0.0f, -1.0f);
glColor3f(1.0f, 0.0f, 0.0f);
glVertex3d(0.0, -1.0, -1.0);
glEnd();
Then a vertex shader like this:
void main(void) {
gl_Position = ftransform();
gl_FrontColor = gl_Color;
}
with a fragment shader like this:
void main() {
gl_FragColor = gl_Color;
}
will transmit the colors through, just like if you were using the fixed-functionality pipeline.
回答2:
If you want to do mult-pass rendering, i.e. if you have rendered to the framebuffer and want to to a second render pass where you use the previous rendering than the answer is:
- Render the first pass to a texture
- Bind this texture for the second pass
- Access the privously rendered pixel in the shader
Shader code for 3.2:
uniform sampler2D mytex; // texture with the previous render pass
layout(pixel_center_integer) in vec4 gl_FragCoord;
// will give the screen position of the current fragment
void main()
{
// convert fragment position to integers
ivec2 screenpos = ivec2(gl_FragCoord.xy);
// look up result from previous render pass in the texture
vec4 color = texelFetch(mytex, screenpos, 0);
// now use the value from the previous render pass ...
}
Another methods of processing a rendered image would be OpenCL with OpenGL -> OpenCL interop. This allows more CPU like computationing.
回答3:
If what you're calling "current value of the fragment" is the pixel color value that was in the render target before your fragment shader runs, then no, it is not available.
The main reason for that is that potentially, at the time your fragment shader runs, it is not known yet. Fragment shaders run in parallel, potentially (depending on which hardware) affecting the same pixel, and a separate block, reading from some sort of FIFO, is usually responsible to merge those together later on. That merging is called "Blending", and is not part of the programmable pipeline yet. It's fixed function, but it does have a number of different ways to combine what your fragment shader generated with the previous color value of the pixel.
回答4:
You need to sample texture at current pixel coordinates, something like this
vec4 pixel_color = texture2D(tex, gl_TexCoord[0].xy);
Note,- as i've seen texture2D is deprecated in GLSL 4.00 specification - just look for similar texture... fetch functions.
Also sometimes it is better to supply your own pixel coordinates instead of gl_TexCoord[0].xy - in that case write vertex shader something like:
varying vec2 texCoord;
void main(void)
{
gl_Position = vec4(gl_Vertex.xy, 0.0, 1.0 );
texCoord = 0.5 * gl_Position.xy + vec2(0.5);
}
And in fragment shader use that texCoord variable instead of gl_TexCoord[0].xy.
Good luck.
回答5:
The entire point of your fragment shader is to decide what the output color is. How you do that depends on what you are trying to do.
You might choose to set things up so that you get an interpolated color based on the output of the vertex shader, but a more common approach would be to perform a texture lookup in the fragment shader using texture coordinates passed in the from the vertex shader interpolants. You would then modify the result of your texture lookup according to your chosen lighting calculations and whatever else your shader is meant to do and then write it into gl_FragColor.
回答6:
The GPU pipeline has access to the underlying pixel info immediately after the shaders run. If your material is transparent, the blending stage of the pipeline will combine all fragments.
Generally objects are blended in the order that they are added to a scene, unless they have been ordered by a z-buffering algo. You should add your opaque objects first, then carefully add your transparent objects in the order to be blended.
For example, if you want a HUD overlay on your scene, you should just create a screen quad object with an appropriate transparent texture, and add this to your scene last.
Setting the SRC and DST blending functions for transparent objects gives you access to the previous blend in many different ways.
You can use the alpha property of your output color here to do really fancy blending. This is the most efficient way to access framebuffer outputs (pixels), since it works in a single pass (Fig. 1) of the GPU pipeline.
Fig. 1 - Single Pass
If you really need multi pass (Fig. 2), then you must target the framebuffer outputs to an extra texture unit rather than the screen, and copy this target texture to the next pass, and so on, targeting the screen in the final pass. Each pass requires at least two context switches.
The extra copying and context switching will degrade rendering performance severely. Note that multi-threaded GPU pipelines are not much help here, since multi pass is inherently serialized.
Fig. 2 - Multi Pass
I have resorted to a verbal description with pipeline diagrams to avoid deprecation, since shader language (Slang/GLSL) is subject to change.
回答7:
how-do-i-get-the-current-color-of-a-fragment
Some say it cannot be done, but I say this works for me:
//Toggle blending in one sense, while always disabling it in the other.
void enableColorPassing(BOOL enable) {
//This will toggle blending - and what gl_FragColor is set to upon shader execution
enable ? glEnable(GL_BLEND) : glDisable(GL_BLEND);
//Tells gl - "When blending, change nothing"
glBlendFunc(GL_ONE, GL_ZERO);
}
After that call, gl_FragColor will equal the color buffer's clear color the first time the shader runs on each pixel, and the output each run will be the new input upon each successive run.
Well, at least it works for me.
来源：https://stackoverflow.com/questions/2740874/how-do-i-get-the-current-color-of-a-fragment