Java: detect control characters which are not correct for JSON

亡梦爱人 提交于 2019-12-03 05:19:55

Will Character.isISOControl(...) do? Incidentally, UTF-16 is an encoding of Unicode codepoints... Are you going to be operating at the byte level, or at the character/codepoint level? I recommend leaving the mapping from UTF-16 to character streams to Java's core APIs...

Even if it's not very specific, I would assume that they refer to the "control" character category from the Unicode specification.

In Java, you can check if a character c is a Unicode control character with the following expression: Character.getType(c) == Character.CONTROL.

I believe the Unicode definition of a control character is:

The 65 characters in the ranges U+0000..U+001F and U+007F..U+009F.

That's their definition of a control code, but the above is followed by the sentence "Also known as control characters.", so...

toongeorges

I know the question has been asked a couple of years ago, but I am replying anyway, because the accepted answer is not correct.

Character.isISOControl(int codePoint) 

does the following check:

(codePoint >= 0x00 && codePoint <= 0x1F) || (codePoint >= 0x7F && codePoint <= 0x9F);

The JSON specification defines at https://tools.ietf.org/html/rfc7159:

  1. Strings

    The representation of strings is similar to conventions used in the C family of programming languages. A string begins and ends with quotation marks. All Unicode characters may be placed within the quotation marks, except for the characters that must be escaped: quotation mark, reverse solidus, and the control characters (U+0000 through U+001F).

Character.isISOControl(int codePoint) 

will flag all characters that need to be escaped (U+0000-U+001F), though it will also flag characters that do not need to be escaped (U+007F-U+009F). It is not required to escape the characters (U+007F-U+009F).

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