I have a users
table and a one-to-zero/one relation with a businesses
table (users.user_id => businesses.user_id). On my users
table I have a discriminator which tells me if the user is of type business and therefore I need to have details on the businesses
table as well.
I want to create my Users with my factory which currently is working and then only create business details where the discriminator points to a business account.
I have three options in my mind:
- Create from users factory and then using '->each()' do some checks on the discriminator and create a new business user using a the factory. However I cannot pass to the business factory the
user_id
that the user was assigned. - First create the users. Then in my Business seeder, retrieve all Users that match a 'business' discriminator. Then for all of these users run a factory that creates the business details. But again, I would have to link somehow the
user_id
of the already create user with the business factoryuser_id
. - In my business factory, create a new User and retrieve the id, thus making the link between
users.user_id
andbusiness.user_id
. However I am using a random generator foruser.user_type
so even if I have thebusinesses
table filled it might be for users that have the discriminator as 'personal'.
Is there another way? Can I pass arguments from my Seeder to the factory?
The attributes you pass to the create
function will be passed into your model definition callback as the second argument.
In your case you don't even need to access those attributes, since they'll automatically be merged in:
$business = factory(App\Business::class)->create();
factory(App\User::class, 5)->create([
'business_id' => $business->id,
]);
Adapt this to your needs.
My code for adding polymorphic 'Admin' users was:
// run model factory
factory(App\Admin::class, 3)->create()->each(function ($admin) {
$admin->user()->save(
// solved: https://laravel.com/docs/master/database-testing#using-factories (Overriding attributes)
factory(App\User::class)->make([
'userable_id' => $admin->id,
'userable_type' => App\Admin::class
])
);
});
Hope this helps.
来源:https://stackoverflow.com/questions/32378215/how-to-pass-arguments-to-laravel-factories