问题
I have the following code to capture a ^C from the terminal and gracefully shutdown my Express app:
process.on('SIGINT', () => {
console.log('SIGINT received ...');
console.log('Shutting down the server');
server.close(() => {
console.log('Server has been shutdown');
console.log('Exiting process ...');
process.exit(0);
});
});
However if I start my node instance with --inspect
, then the above code fails to stop the inspector and the Chrome debugger. When I restart my application, I get the following error:
Starting inspector on 127.0.0.1:9229 failed: address already in use
How do I gracefully stop my app to avoid this error?
Full code available here.
回答1:
It seems that VSCode, Puppeteer, nodemon, express, etc. causes this problem, you ran a process in the background or just closed the debugging area [browser, terminal, etc. ] or whatever , anyway, you can in CMD run
$ ps ax | grep node
then
$ killall -9 node
it is not the best solution, also, i may suggest that you look for the process using this port then send close signal
$ sudo ss -lptn 'sport = :9229'
OR
$ sudo netstat -nlp | grep :9229
OR
$ sudo lsof -n -i :9229 | grep LISTEN
THEN:
$ sudo kill <pid>
OR JUST [the two steps in one]
$ sudo kill `sudo lsof -t -i:9229`
OR
$ sudo kill $(sudo lsof -t -i:9229)
回答2:
I had the same terminal error from nodemon, even though I thought I'd quit all terminal processes, but simply quitting VSCode and reopening solved for me (thanks to KhogaEslam's answer for the hint).
Hope this helps someone else too!
回答3:
was at a node docker. with ss
, complete, if u know the port is open:
kill `ss -lptn 'sport = :THE_PORT' | tail -n1 | cut -d, -f2 | cut -d= -f2`
来源:https://stackoverflow.com/questions/47609400/how-to-stop-the-node-js-inspector-chrome-debugger-on-sigint