Regex to get the words after matching string

问题

Below is the Content:

Subject:
    Security ID:        S-1-5-21-3368353891-1012177287-890106238-22451
    Account Name:       ChamaraKer
    Account Domain:     JIC
    Logon ID:       0x1fffb

Object:
    Object Server:  Security
    Object Type:    File
    Object Name:    D:\ApacheTomcat\apache-tomcat-6.0.36\logs\localhost.2013-07-01.log
    Handle ID:  0x11dc

I need to capture the words after the Object Name: word in that line. Which is D:\ApacheTomcat\apache-tomcat-6.0.36\logs\localhost.2013-07-01.log. I hope somebody can help me with this.

^.*\bObject Name\b.*$ matches - Object Name

回答1:

The following should work for you:

[\n\r].*Object Name:\s*([^\n\r]*)

Working example

Your desired match will be in capture group 1.

---

[\n\r][ \t]*Object Name:[ \t]*([^\n\r]*)

Would be similar but not allow for things such as " blah Object Name: blah" and also make sure that not to capture the next line if there is no actual content after "Object Name:"

回答2:

But I need the match result to be ... not in a match group...

For what you are trying to do, this should work. \K resets the starting point of the match.

\bObject Name:\s+\K\S+

You can do the same for getting your Security ID matches.

\bSecurity ID:\s+\K\S+

回答3:

You're almost there. Use the following regex (with multi-line option enabled)

\bObject Name:\s+(.*)$

The complete match would be

Object Name:   D:\ApacheTomcat\apache-tomcat-6.0.36\logs\localhost.2013-07-01.log

while the captured group one would contain

D:\ApacheTomcat\apache-tomcat-6.0.36\logs\localhost.2013-07-01.log

---

If you want to capture the file path directly use

(?m)(?<=\bObject Name:).*$

回答4:

This might work out for you depending on which language you are using

(?<=Object Name:).*

It's a positive lookbehind assertion. More info could be found here

It won't work with java script though. In your comment I read that you're using it for logstash. If you are using GROK parsing for logstash then it would work. You can verify itself here

https://grokdebug.herokuapp.com/

回答5:

Here's a quick perl script to get what you need. Needs some whitespace chomping.

#!/bin/perl

$sample = <<END;
Subject:
  Security ID:        S-1-5-21-3368353891-1012177287-890106238-22451
  Account Name:       ChamaraKer
  Account Domain:     JIC
  Logon ID:       0x1fffb

Object:
  Object Server:  Security
  Object Type:    File
  Object Name:    D:\\ApacheTomcat\\apache-tomcat-6.0.36\\logs\\localhost.2013- 07-01.log
  Handle ID:  0x11dc
END

my @sample_lines = split /\n/, $sample;
my $path;

foreach my $line (@sample_lines) {
  ($path) = $line =~ m/Object Name:([^s]+)/g;
  if($path) {
    print $path . "\n";
  }
}

回答6:

This is python solution.

import re

line ="""Subject:
    Security ID:        S-1-5-21-3368353891-1012177287-890106238-22451
    Account Name:       ChamaraKer
    Account Domain:     JIC
    Logon ID:       0x1fffb

Object:
    Object Server:  Security
    Object Type:    File
    Object Name:    D:\ApacheTomcat\apache-tomcat-6.0.36\logs\localhost.2013-07-01.log
    Handle ID:  0x11dc"""



regex = (r'Object Name:\s+(.*)')
match1= re.findall(regex,line)
print (match1)

*** Remote Interpreter Reinitialized  ***
>>> 
['D:\\ApacheTomcat\x07pache-tomcat-6.0.36\\logs\\localhost.2013-07-01.log']
>>> 

来源：https://stackoverflow.com/questions/19193251/regex-to-get-the-words-after-matching-string