问题
I was trying to get some code done for class:
public int getValue(char value) {
if (value == 'y') return this.y;
else if (value == 'x') return this.x;
Since I might not be able to return anything in the end, it told me to do this at the end:
return value;
This surprised me because the return type for the method was of type int
. Yet, it was telling me to return a char
! I'm using eclipse, and accustomed to the endless number of warnings and stuff, this was a major surprise.
So, is a char
really an int
? Why is this happening?
回答1:
The Java Language Specification states
When a return statement with an
Expression
appears in a method declaration, theExpression
must be assignable (§5.2) to the declared return type of the method, or a compile-time error occurs.
where the rules governing whether one value is assignable to another is defined as
Assignment contexts allow the use of one of the following:
- a widening primitive conversion (§5.1.2)
and
19 specific conversions on primitive types are called the widening primitive conversions:
char
toint
,long
,float
, or `double
and finally
A widening primitive conversion does not lose information about the overall magnitude of a numeric value in the following cases, where the numeric value is preserved exactly: [...]
A widening conversion of a
char
to an integral typeT
zero-extends the representation of thechar
value to fill the wider format.
In short, a char
value as the expression of a return
statement is assignable to a return type of int
through widening primitive conversion.
回答2:
A char
is smaller than an int
, so you can return it and it will prepend zeroes to make a longer number. That's not the right thing to return - in your case I'd probably throw an exception instead; however, the editor suggested it because it's something that you're allowed to return and you need to return something.
The following code is legal:
char c = 'h';
int i = c;
回答3:
In computing, everything is numbers! Just bits and bytes.
int
, char
, byte
, short
and long
are just numbers. A char
is just a number that the compiler knows is usually used for displaying the character represented by the particular number (e.g. 32 = space, 48 = zero, etc).
A String is a sequence of numbers and other stuff, so a bit more complicated. We don't want to go there.
An int
is a four byte number and a char
is a two byte number, so you can fit any char
number in an int
.
The designers of Java just decided they would let you convert from char to int without requiring any special casts or conversions.
回答4:
A char
is not an int
. However, it is an integral type. That is to say, it's considered to be a whole number that can be converted to and from other integral types (long
,short
,byte
and int
), according to the Java Language Specification.
Basically what this means is that it is assignment-compatible to int
. Its value is between 0 and 65535, and if you assign it to an int
or cast it to an int
and print it, you'll get the UTF-16 value of the character it represents.
回答5:
By definition (in java) a char is an 8bit unsigned integer. (0 to 256)
An int an 32bit signed integer. (−2.147.483.648 to 2.147.483.647)
char a = 65; //65 is the ASCII Number of 'A'
System.out.println(a);
>>> A
b = a + 1
System.out.println(b);
>>> B
java autoboxing converts char to int and vice versa
回答6:
There is an implicit and natural conversion from int
to char
and vice-versa. Note that you thus have the usual arithmetic defined on char
m which comes very handy when you want, let's say, to iterate on the alphabet :
for (char c='a' ; c<='z' ; c++) { ... }
However, note that a char
is 2 bytes long whereas an int
is 4 bytes long, so casting an int
down to a char
may result in an integer overflow.
回答7:
Hope this little example solves your confusion:
public int getValue(int value) {
if (value == 'y')
return this.y;
else if (value == 'x')
return this.x;
}
If you pass char
as an int
like getValue('x')
, it would return the value of the int
.
来源:https://stackoverflow.com/questions/30717898/java-char-is-also-an-int