fgetc does not identify EOF [duplicate]

问题

This question already has answers here:

Difference between int and char in getchar/fgetc and putchar/fputc? (2 answers)

Closed last year.

The program below runs fine on various Solaris/Linux flavours, but not on AIX. However, if I replace while(c!=EOF) with while(c!=0xff) on AIX it runs completely fine.

Any thoughts? I checked the fgetc man page on AIX, and it should return the EOF constant!

---

#include <stdio.h>
#include<unistd.h>
#include <string.h>
int main() {
char c;
  FILE *fp;
  fp = fopen("a.txt", "r");
     c=fgetc(fp);
     while(c!=EOF)
        {
        c=fgetc(fp);
        printf("%d",c);
        }

  fclose(fp);
return 0;
}

回答1:

The return value of fgetc is int not char. So change

char c;

to

int c;

来源：https://stackoverflow.com/questions/3977223/fgetc-does-not-identify-eof