问题
I made two test bash scripts on Linux to make the problem clear.
TestScript1 looks like: echo "TestScript1 Arguments:"
echo "$1"
echo "$2"
echo "$#"
./testscript2 $1 $2
TestScript2 looks like:
echo "TestScript2 Arguments received from TestScript1:"
echo "$1"
echo "$2"
echo "$#"
When i execute testscript1 in the following way:
./testscript1 "Firstname Lastname" testmail@domain.com
The desired Output should be:
TestScript1 Arguments:
Firstname Lastname
testmail@domain.com
2
TestScript2 Arguments received from TestScript1:
Firstname Lastname
testmail@domain.com
2
But the actual output is:
TestScript1 Arguments:
Firstname Lastname
testmail@domain.com
2
TestScript2 Arguments received from TestScript1:
Firstname
Lastname
3
How do i solve this problem? I want to get the desired output instead of the actual output.
回答1:
Quote your args in Testscript 1:
echo "TestScript1 Arguments:"
echo "$1"
echo "$2"
echo "$#"
./testscript2 "$1" "$2"
回答2:
You need to use : "$@"
(WITH the quotes) or "${@}"
(same, but also telling the shell where the variable name starts and ends).
(and do NOT use : $@
, or "$*"
, or $*
).
ex:
#testscript1:
echo "TestScript1 Arguments:"
for an_arg in "$@" ; do
echo "${an_arg}"
done
echo "nb of args: $#"
./testscript2 "$@" #invokes testscript2 with the same arguments we received
I'm not sure I understood your other requirement ( you want to invoke './testscript2' in single quotes?) so here are 2 wild guesses (changing the last line above) :
'./testscript2' "$@" #only makes sense if "/path/to/testscript2" containes spaces?
./testscript2 '"some thing" "another"' "$var" "$var2" #3 args to testscript2
Please give me the exact thing you are trying to do
edit: after his comment saying he attempts tesscript1 "$1" "$2" "$3" "$4" "$5" "$6" to run : salt 'remote host' cmd.run './testscript2 $1 $2 $3 $4 $5 $6'
You have many levels of intermediate: testscript1 on host 1, needs to run "salt", and give it a string launching "testscrit2" with arguments in quotes...
You could maybe "simplify" by having:
#testscript1
#we receive args, we generate a custom script simulating 'testscript2 "$@"'
theargs="'$1'"
shift
for i in "$@" ; do
theargs="${theargs} '$i'"
done
salt 'remote host' cmd.run "./testscript2 ${theargs}"
if THAt doesn't work, then instead of running "testscript2 ${theargs}", replace THE LAST LINE above by
echo "./testscript2 ${theargs}" >/tmp/runtestscript2.$$ #generate custom script locally ($$ is current pid in bash/sh/...)
scp /tmp/runtestscript2.$$ user@remotehost:/tmp/runtestscript2.$$ #copy it to remotehost
salt 'remotehost' cmd.run "./runtestscript2.$$" #the args are inside the custom script!
ssh user@remotehost "rm /tmp/runtestscript2.$$" #delete the remote one
rm /tmp/runtestscript2.$$ #and the local one
回答3:
I found following program works for me
test1.sh
a=xxx
test2.sh $a
in test2.sh you use $1
to refer variable a
in test1.sh
echo $1
The output would be xxx
来源:https://stackoverflow.com/questions/16988427/calling-one-bash-script-from-another-script-passing-it-arguments-with-quotes-and