JSplitPane splitting 50% precisely

徘徊边缘 提交于 2019-12-03 02:19:22

Use

setResizeWeight(.5d);

[...] A value of 0, the default, indicates the right/bottom component gets all the extra space (the left/top component acts fixed), where as a value of 1 specifies the left/top component gets all the extra space (the right/bottom component acts fixed). [...]

You should use setDividerLocation(double proportionalLocation) to determine the initial space distribution of the JSplitPane, and then call setResizeWeight(double) with the same value to ensure that the panes are resized in proportion.

Also, be aware: Calling setDividerLocation(double) before the JSplitPane is visible will not work correctly, as the space calculation is based on the Component's current size. Instead you need to involve a nasty hack, such as overriding the JPanel's paint method that contains the JSplitPane:

private boolean painted;

@Override
public void paint(Graphics g) {
    super.paint(g);

    if (!painted) {
        painted = true;
        splitPane.setDividerLocation(0.25);
    }
}

I had a similar problem and I solved it by using a component listener in the parent container and set the divider location on the first resize. Initialise a variable firstResize to true and add this into the parent container constructor:

addComponentListener(new ComponentAdapter(){
    @Override
    public void componentResized(ComponentEvent e) {
        if(firstResize){
            splitPane.setDividerLocation(0.5);
            firstResize = false;
        }
    }
});

This should cause the divider to be centred when the parent container size is first set.

John

The solutions here do not take into account the case where the user moves the divider (i.e. a variable divider location). A complete example that takes this into account is available here:

How do you get JSplitPane to keep the same proportional location if the user has moved the location of the divider

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