I am wondering why :sprint
reports xs = _
in this case:
Prelude> xs = map (+1) [1..10]
Prelude> length xs
10
Prelude> :sprint xs
xs = _
but not in this case:
Prelude> xs = map (+1) [1..10] :: [Int]
Prelude> length xs
10
Prelude> :sprint xs
xs = [_,_,_,_,_,_,_,_,_,_]
Note: I am running ghci
with -XNoMonomorphismRestriction
. Does it have to do with the fact that the type of xs
is polymorphic in the first case but not in the second? I'd like to know what's going on internally.
The gist is that the with the polymorphic xs
it has a type of the form
xs :: Num a => [a]
typeclasses under the hood are really just functions, they take an extra argument that GHC automatically fills that contains a record of the typeclasses functions. So you can think of xs
having the type
xs :: NumDict a -> [a]
So when you run
Prelude> length xs
It has to choose some value for a
, and find the corresponding NumDict
value. IIRC it'll fill it with Integer
, so you're actually calling a function with and checking the length of the resulting list.
When you then :sprint
xs
, you once again fill in that argument, this time with a fresh type variable. But the point is that you're getting an entirely different list, you gave it a different NumDict
so it's not forced in any way when you called length
before.
This is very different then with the explicitly monomorphic list since there really is only one list there, there's only one value to force so when you call length, it forces it for all future uses of xs
.
To make this a bit clearer, consider the code
data Smash a = Smash { smash :: a -> a -> a }
-- ^ Think of Monoids
intSmash :: Smash Int
intSmash = Smash (+)
listSmash :: Smash [a]
listPlus = Smash (++)
join :: Smash a -> [a] -> a
join (Smash s) xs = foldl1' s xs
This is really what type classes are like under the hood, GHC would automatically fill in that first Smash a
argument for us. Now your first example is like join
, we can't make any assumptions about what the output will be as we apply it to different types, but your second example is more like
join' :: [Int] -> Int
join' = join intSmash
来源:https://stackoverflow.com/questions/21518584/sprint-for-polymorphic-values