问题
I have two files: script1.py and script2.py. I need to invoke script2.py from script1.py and return the value from script2.py back to script1.py. But the catch is script1.py actually runs script2.py through os.
script1.py:
import os
print(os.system("script2.py 34"))
script2.py
import sys
def main():
x="Hello World"+str(sys.argv[1])
return x
if __name__ == "__main__":
x= main()
As you can see, I am able to get the value into script2, but not back to script1. How can I do that? NOTE: script2.py HAS to be called as if its a commandline execution. Thats why I am using os.
回答1:
Ok, if I understand you correctly you want to:
- pass an argument to another script
- retrieve an output from another script to original caller
I'll recommend using subprocess module. Easiest way would be to use check_output() function.
Run command with arguments and return its output as a byte string.
Sample solution:
script1.py
import sys
import subprocess
s2_out = subprocess.check_output([sys.executable, "script2.py", "34"])
print s2_out
script2.py:
import sys
def main(arg):
print("Hello World"+arg)
if __name__ == "__main__":
main(sys.argv[1])
回答2:
The recommended way to return a value from one python "script" to another is to import the script as a Python module and call the functions directly:
import another_module
value = another_module.get_value(34)
where another_module.py
is:
#!/usr/bin/env python
def get_value(*args):
return "Hello World " + ":".join(map(str, args))
def main(argv):
print(get_value(*argv[1:]))
if __name__ == "__main__":
import sys
main(sys.argv)
You could both import another_module
and run it as a script from the command-line. If you don't need to run it as a command-line script then you could remove main()
function and if __name__ == "__main__"
block.
See also, Call python script with input with in a python script using subprocess.
来源:https://stackoverflow.com/questions/30664263/return-value-from-one-python-script-to-another