问题
I am trying to convert a long filename to a short filename (8.3) on Windows.
A batch-file with a command line argument works as intended:
short.bat:
@echo OFF
echo %~s1
calling short.bat C:\Documents and Settings\User\NTUSER.DAT
returns C:\DOCUM~1\USER\NTUSER.DAT
However, I don't like having an extra .bat-file for this. I would rather call cmd.exe
with the whole command from a ruby script.
How can I do this?
As an intermediate step I tried to hardcode the path in the batch-file, but that does not work:
short1.bat:
@echo OFF
SET filename="C:\Documents and Settings\User\NTUSER.DAT"
echo %filename%
echo %~sfilename%
echo %filename%
works, but echo %~sfilename%
gives the following error:
The following usage of the path operator in batch-parameter
substitution is invalid: %~sfilename%
For valid formats type CALL /? or FOR /?
If short1.bat works, how can I convert this into a one-liner that can be called with cmd.exe \c ...
?
There is another question (how to get DOS path instead of Windows path), however that one is specifically asking for the path of the current directory.
回答1:
cmd /c for %A in ("C:\Documents and Settings\User\NTUSER.DAT") do @echo %~sA
回答2:
Replace the filename.txt to the filename you want to convert to 8.3
dir /x filename.txt
You will then have to split the result with whitespace as your delimiter (\s in regex). Then the value with the ~ is your short filename. If your filename is short to begin with, then you won't find a string containing a ~.
来源:https://stackoverflow.com/questions/10227144/convert-long-filename-to-short-filename-8-3-using-cmd-exe