PHP: How to check whether the URL is Youtube's or vimeo's

霸气de小男生 提交于 2019-12-02 20:58:56

As others have noted in the comments, this is a quick and dirty solution that does not handle edge cases well. If the url contains "youtube"(example.com/youtube) it will return a false positive. The parse_url() solution mentioned below is a much more robust solution.


Regular expressions work well for this type of thing, but often strpos or substr are faster performance wise. Check out the PHP documentation for preg_match(). Below the examples there is a note for exactly this thing.

Here is prototype code:

function videoType($url) {
    if (strpos($url, 'youtube') > 0) {
        return 'youtube';
    } elseif (strpos($url, 'vimeo') > 0) {
        return 'vimeo';
    } else {
        return 'unknown';
    }
}

Obviously returning a string isn't the best idea, but you get the point. Substitute your own business logic.

Use the parse_url function to split the URL up and then just do your normal checks

$url = 'http://www.youtube.com/watch?v=rj18UQjPpGA&feature=player_embedded';
$parsed = parse_url($url);

Will give you this array

array
  'scheme' => string 'http' (length=4)
  'host' => string 'www.youtube.com' (length=15)
  'path' => string '/watch' (length=6)
  'query' => string 'v=rj18UQjPpGA&feature=player_embedded' (length=37)

Surprising no one has mentioned that youtube urls can also contain the domain 'youtu.be' in which case all of the above solutions would have to be adapted to cater for that eventuality.

I recently wrote this function to do exactly this, hopefully it's useful to someone:

    /**
 * [determineVideoUrlType used to determine what kind of url is being submitted here]
 * @param  string $url either a YouTube or Vimeo URL string
 * @return array will return either "youtube","vimeo" or "none" and also the video id from the url
 */

public function determineVideoUrlType($url) {


    $yt_rx = '/^((?:https?:)?\/\/)?((?:www|m)\.)?((?:youtube\.com|youtu.be))(\/(?:[\w\-]+\?v=|embed\/|v\/)?)([\w\-]+)(\S+)?$/';
    $has_match_youtube = preg_match($yt_rx, $url, $yt_matches);


    $vm_rx = '/(https?:\/\/)?(www\.)?(player\.)?vimeo\.com\/([a-z]*\/)*([‌​0-9]{6,11})[?]?.*/';
    $has_match_vimeo = preg_match($vm_rx, $url, $vm_matches);


    //Then we want the video id which is:
    if($has_match_youtube) {
        $video_id = $yt_matches[5]; 
        $type = 'youtube';
    }
    elseif($has_match_vimeo) {
        $video_id = $vm_matches[5];
        $type = 'vimeo';
    }
    else {
        $video_id = 0;
        $type = 'none';
    }


    $data['video_id'] = $video_id;
    $data['video_type'] = $type;

    return $data;

}

You can use preg_match():

$u1="http://vimeo.com/24456787";
$u2="http://www.youtube.com/watch?v=rj18UQjPpGA&feature=player_embedded";

if(preg_match('/http:\/\/(www\.)*vimeo\.com\/.*/',$u1)){
    // do vimeo stuff
    echo "Vimeo URL found!\n";
}

if(preg_match('/http:\/\/(www\.)*youtube\.com\/.*/',$u2)){
    // do youtube stuff
    echo "YouTube URL found!\n";
}

Since all you want to do is check for the presence of a string, use stripos. If it doesn't have youtube.com or vimeo.com in it, the url is malformed, right? stripos is case insensitive, too.

if(stripos($url,'youtu')===false){
    //must be vimeo
    } else {
    //is youtube
    }

You can try my solution:

function checkServer( $domains=array(), $url ) {
    foreach ( $domains as $domain ) {
        if ( strpos($url, $domain ) > 0) {
            return true;
        } else {
            return false;
        }
    }
}

Use:

if( checkServer(array("youtube.com","youtu.be"), $url ) ) {
    //is Youtube url
}
elseif( checkServer(array("vimeo.com"), $url ) ) {
    //is Vimeo
}
elseif ( checkServer(array("any domain"), $url ) ) {
    //is Any Domain
}else {
    //unknow domain
}

Use regular expressions. What language are you using?

Edit: noticed your tag was php. It would be something like this:

<?php
// get host name from URL
preg_match('@^(?:http://)?([^/]+)@i',
    "http://www.youtube.com/index.html", $matches);
$host = $matches[1];

// get last two segments of host name
preg_match('/[^.]+\.[^.]+$/', $host, $matches);
echo {$matches[0]}\n"; //youtube.com
?>
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