Why jackson is serializing transient member also?

谁说胖子不能爱 提交于 2019-12-02 20:15:24
Eugen

The reason Jackson serializes the transient member is because the getters are used to determine what to serialize, not the member itself - and since y has a public getter, that gets serialized. If you want to change that default and have Jackson use fields - simply do:

om.setVisibilityChecker(
om.getSerializationConfig().
getDefaultVisibilityChecker().
withFieldVisibility(JsonAutoDetect.Visibility.ANY).
withGetterVisibility(JsonAutoDetect.Visibility.NONE));

Another way to ignore a property on serialization is to do it directly on the class:

@JsonIgnoreProperties(value = { "y" })
public class TestElement {
...

And another way is directly on the field:

public class TestElement {

    @JsonIgnore
    private String y;
...

Hope this helps.

A new way to stop Jackson from serializing and deserializing is to call mapper.configure(MapperFeature.PROPAGATE_TRANSIENT_MARKER, true).

idelvall

I can't make comments so complete the previous response here, changing the (now) deprecated method setVisibilityChecker and adding a missing clause for booleans:

mapper.setVisibility(
    mapper.getSerializationConfig().
    getDefaultVisibilityChecker().
    withFieldVisibility(JsonAutoDetect.Visibility.ANY).
    withGetterVisibility(JsonAutoDetect.Visibility.NONE).
    withIsGetterVisibility(JsonAutoDetect.Visibility.NONE)
);
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