问题
I just used array_filter to remove entries that had only the value '' from an array, and now I want to apply certain transformations on it depending on the placeholder starting from 0, but unfortunately it still retains the original index. I looked for a while and couldn't see anything, perhaps I just missed the obvious, but my question is...
How can I easily reset the indexes of the array to begin at 0 and go in order in the NEW array, rather than have it retain old indexes?
回答1:
If you call array_values on your array, it will be reindexed from zero.
回答2:
If you are using Array filter do it as follows
$NewArray = array_values(array_filter($OldArray));
回答3:
Use array_values()
:
<?php
$array = array('foo', 'bar', 'baz');
$array = array_filter($array, function ($var) {
return $var !== 'bar';
});
print_r($array); // indexes 0 and 2
print_r(array_values($array)); // indexes 0 and 1
回答4:
I worry about how many programmers have innocently copy/pasted the array_values(array_filter())
method into their codes -- I wonder how many programmers unwittingly ran into problems because of array_filter's greed. Or worse, how many people never discovered that the function purges too many values from the array...
I will present a better alternative for the two-part process of stripping NULL
elements from an array and re-indexing the keys.
However, first, it is extremely important that I stress the greedy nature of array_filter()
and how this can silently monkeywrench your project. Here is an array with mixed values in it that will expose the trouble:
$array=['foo',NULL,'bar',0,false,null,'0',''];
Null values will be removed regardless of uppercase/lowercase.
But look at what remains in the array when we use array_values() & array_filter():
array_values(array_filter($array));
Output array ($array):
array (
0 => 'foo',
1 => 'bar'
)
// All empty, zero-ish, falsey values were removed too!!!
Now look at what you get with my method that uses array_walk() & is_null() to generate a new filtered array:
array_walk($array,function($v)use(&$filtered){if(!is_null($v)){$filtered[]=$v;}});
This can be written over multiple lines for easier reading/explaining:
array_walk( // iterate each element of an input array
$array, // this is the input array
function($v)use(&$filtered){ // $v is each value, $filter (output) is declared/modifiable
if(!is_null($v)){ // this literally checks for null values
$filtered[]=$v; // value is pushed into output with new indexes
}
}
);
Output array ($filter):
array (
0 => 'foo',
1 => 'bar',
2 => 0,
3 => false,
4 => '0',
5 => '',
)
With my method you get your re-indexed keys, all of the non-null values, and none of the null values. A clean, portable, reliable one-liner for all of your array null-filtering needs. Here is a demonstration.
Similarly, if you want to remove empty, false, and null elements (retaining zeros), these four methods will work:
var_export(array_values(array_diff($array,[''])));
or
var_export(array_values(array_diff($array,[null])));
or
var_export(array_values(array_diff($array,[false])));
or
var_export(array_values(array_filter($array,'strlen')));
Output:
array (
0 => 'foo',
1 => 'bar',
2 => 0,
3 => '0',
)
Finally, for anyone who prefers the syntax of language constructs, you can also just push qualifying values into a new array to issue new indexes.
$array=['foo', NULL, 'bar', 0, false, null, '0', ''];
$result = [];
foreach ($array as $value) {
if (strlen($value)) {
$result[] = $value;
}
}
var_export($result);
来源:https://stackoverflow.com/questions/3401850/after-array-filter-how-can-i-reset-the-keys-to-go-in-numerical-order-starting