问题
Once I have all the files I require in a particular folder, I would like my python script to zip the folder contents.
Is this possible?
And how could I go about doing it?
回答1:
Adapted version of the script is:
#!/usr/bin/env python
from __future__ import with_statement
from contextlib import closing
from zipfile import ZipFile, ZIP_DEFLATED
import os
def zipdir(basedir, archivename):
assert os.path.isdir(basedir)
with closing(ZipFile(archivename, "w", ZIP_DEFLATED)) as z:
for root, dirs, files in os.walk(basedir):
#NOTE: ignore empty directories
for fn in files:
absfn = os.path.join(root, fn)
zfn = absfn[len(basedir)+len(os.sep):] #XXX: relative path
z.write(absfn, zfn)
if __name__ == '__main__':
import sys
basedir = sys.argv[1]
archivename = sys.argv[2]
zipdir(basedir, archivename)
Example:
C:\zipdir> python -mzipdir c:\tmp\test test.zip
It creates 'C:\zipdir\test.zip'
archive with the contents of the 'c:\tmp\test'
directory.
回答2:
On python 2.7 you might use: shutil.make_archive(base_name, format[, root_dir[, base_dir[, verbose[, dry_run[, owner[, group[, logger]]]]]]]).
base_name archive name minus extension
format format of the archive
root_dir directory to compress.
For example
shutil.make_archive(target_file, format="bztar", root_dir=compress_me)
回答3:
Here is a recursive version
def zipfolder(path, relname, archive):
paths = os.listdir(path)
for p in paths:
p1 = os.path.join(path, p)
p2 = os.path.join(relname, p)
if os.path.isdir(p1):
zipfolder(p1, p2, archive)
else:
archive.write(p1, p2)
def create_zip(path, relname, archname):
archive = zipfile.ZipFile(archname, "w", zipfile.ZIP_DEFLATED)
if os.path.isdir(path):
zipfolder(path, relname, archive)
else:
archive.write(path, relname)
archive.close()
来源:https://stackoverflow.com/questions/296499/how-do-i-zip-the-contents-of-a-folder-using-python-version-2-5