问题
I need some help with the JPA Framework. I've read some answers "kind of" about this topic but I couldn't reach any conclusion.
First heres an examplo of the design i'm wooking with.
@BusinessObject
public class ClassA {
@Column(name = "ID", nullable = false)
private Long id;
@OneToMany(mappedBy = "classAAttr")
private Collection<ClassAB> classABCollection;
//STUFF AND OTHER COLUMNS.....
}
public class ClassAB {
@Column(name = "ID", nullable = false)
private Long id;
@JoinColumn(name = "TABLE_A_ID", referencedColumnName = "ID")
@ManyToOne
private ClassA classAAttr;
@JoinColumn(name = "TABLE_B_ID", referencedColumnName = "ID")
@ManyToOne
private ClassB classBAttr;
//STUFF AND OTHER COLUMNS.....
}
@BusinessObject
public class ClassB {
@Column(name = "ID", nullable = false)
private Long id;
@Column(name = "ORDERCLAUSE", nullable = false)
private String orderClause;
//STUFF AND OTHER COLUMNS.....
}
So I need to order the classABCollection in ClassA by the orderClause attribute in ClassB, but I can't find the right @OrderBy() clause AND/OR location for it.
I've read some things about the Comparator Interface but, unfortunately, due to business policy, I need to be sure that there is no other way...
How Should I Do It?
Thank you guys in advance.
回答1:
The API docs for @OrderBy note:
The property or field name must correspond to that of a persistent property or field of the associated class or embedded class within :
http://docs.oracle.com/javaee/6/api/javax/persistence/OrderBy.html
so sorting AB in A by a property of B is not possible.
The alternatives are to write a query or do an in memory sort by some means. Hibernate, for example, has an @Sort
annotation which you can use to apply an in-memory sort on load, either by having the target Entity implement Comparable or by specifying a Comparator:
See section 2.4.6.1:
http://docs.jboss.org/hibernate/annotations/3.5/reference/en/html_single/
来源:https://stackoverflow.com/questions/27299375/jpa-orderby-through-relational-table