Simple IEnumerator use (with example)

被刻印的时光 ゝ 提交于 2019-12-02 15:20:57

Here is the documentation on IEnumerator. They are used to get the values of lists, where the length is not necessarily known ahead of time (even though it could be). The word comes from enumerate, which means "to count off or name one by one".

IEnumerator and IEnumerator<T> is provided by all IEnumerable and IEnumerable<T> interfaces (the latter providing both) in .NET via GetEnumerator(). This is important because the foreach statement is designed to work directly with enumerators through those interface methods.

So for example:

IEnumerator enumerator = enumerable.GetEnumerator();

while (enumerator.MoveNext())
{
    object item = enumerator.Current;
    // Perform logic on the item
}

Becomes:

foreach(object item in enumerable)
{
    // Perform logic on the item
}

As to your specific scenario, almost all collections in .NET implement IEnumerable. Because of that, you can do the following:

public IEnumerator Enumerate(IEnumerable enumerable)
{
    // List implements IEnumerable, but could be any collection.
    List<string> list = new List<string>(); 

    foreach(string value in enumerable)
    {
        list.Add(value + "roxxors");
    }
    return list.GetEnumerator();
}
public IEnumerable<string> Appender(IEnumerable<string> strings)
{
  List<string> myList = new List<string>();
  foreach(string str in strings)
  {
      myList.Add(str + "roxxors");
  }
  return myList;
}

or

public IEnumerable<string> Appender(IEnumerable<string> strings)
{
  foreach(string str in strings)
  {
      yield return str + "roxxors";
  }
}

using the yield construct, or simply

var newCollection = strings.Select(str => str + "roxxors"); //(*)

or

var newCollection = from str in strings select str + "roxxors"; //(**)

where the two latter use LINQ and (**) is just syntactic sugar for (*).

If i understand you correctly then in c# the yield return compiler magic is all you need i think.

e.g.

IEnumerable<string> myMethod(IEnumerable<string> sequence)
{
    foreach(string item in sequence)
    {
         yield return item + "roxxors";
    }
}

I'd do something like:

private IEnumerable<string> DoWork(IEnumerable<string> data)
{
    List<string> newData = new List<string>();
    foreach(string item in data)
    {
        newData.Add(item + "roxxors");
    }
    return newData;
}

Simple stuff :)

Also you can use LINQ's Select Method:

var source = new[] { "Line 1", "Line 2" };

var result = source.Select(s => s + " roxxors");

Read more here Enumerable.Select Method

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