问题
I am Creating the call using the rest api-
try{
// Initiate a new outbound call
$call = $this->client->calls->create(
// to call.
"num2",
// Step 5: Change the 'From' number below to be a valid Twilio number
// that you've purchased or verified with Twilio.
"num1",
array("url" => "url-tw",
'IfMachine'=>'Continue')
);
echo "Started call: " . $call->sid;
} catch(Exception $e){
echo "Error: " . $e->getMessage();
}
and on the url-tw what twiml should I use which can't disconnect the call.
Before I was handling the call using the TwiML but now I have to detect the AnsweredBy option which is only available if I make the call using the REST API so.
for now I m using the same twiml I have used before when I was making calls using the twiML like use the <Dial>
which let to dial again but if I dont use any twiml it disconnect the call.So any advice where I m going wrong.
回答1:
Twilio evangelist here.
The value of the url
parameter should be a publicly accessible URL that returns TwiML containing the instructions that you want Twilio to execute to the caller.
Your PHP to start the call would look like:
// Initiate a new outbound call
$call = $this->client->calls->create(
"num2",
"num1",
array("url" => "http://example.com/answer.php", 'IfMachine'=>'Continue')
);
Then in answer.php
, you can do two things:
- Check the AnsweredBy parameter to see if Twilio detected a machine or a human.
- Generate the Twiml you want to return based on that value
For example to say something different to a machine v a human, you could do something like this in your PHP:
<?php
header("content-type: text/xml");
echo "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n";
?>
<?php if ($_REQUEST['AnsweredBy']=='machine'): ?>
<Response>
<Say>Hello machine</Say>
</Response>
<?php else: ?>
<Response>
<Dial>+15555555555</Dial>
</Response>
<?php endif ?>
Hope that helps.
来源:https://stackoverflow.com/questions/42417185/when-we-make-call-using-rest-api-then-what-twiml-we-use-on-that-url-parameter