Match everything delimited by another regex?

问题

I'm currently trying to make a regex that will find all the sentences in a block of text, and so far I've got this;

(?=(?<!mr)\.|(?<!mrs)\.|\?|!)+

Which will find everything that delimits a sentence. I want the regex to find everything that's contained between what this regex finds, but I don't really know where to go from here.

回答1:

(Moved from your closed newer question)
In your case, the lookbehinds should come before the periods.
Condensing your expression, it is

Update - Between it you could just split discarding delimiters

 # (?:(?<!mr)(?<!mrs)\.|\?|!)+

 (?:
      (?<! mr )
      (?<! mrs )
      \.
   |  \?
   |  !
 )+

Or, split keeping delimiters

 # ((?:(?<!mr)(?<!mrs)\.|\?|!)+)

 (
      (?:
           (?<! mr )
           (?<! mrs )
           \.
        |  \?
        |  !
      )+
 )

回答2:

What about this:

import re

pattern = r'(?=(?<!mr)\.|(?<!mrs)\.|\?|!)+' # I'm assuming this does what you say it does :)
text_block = """long block of sentences"""

sentences = re.split(pattern, text_block)

sentences will be a list containing the resulting substrings. re.split will split text_block up into different elements of the returned list. It splits at each point where pattern matches.

Read about re here:

https://docs.python.org/2/howto/regex.html

EDIT(data imported from your closed newer question):

If you are getting the symbols like ?, ! etc. captured into your returned list aswell, you should try removing the outer parens, like this:

re.split(r"\.(?<!mr)|\.(?<!mrs)|\?|!", somestring)

Ex:

sentences = [s for s in re.split(r"\.(?<!mr)|\.(?<!mrs)|\?|!", somestring) if s]

来源：https://stackoverflow.com/questions/26511010/match-everything-delimited-by-another-regex

标签

python

regex

sentence