问题
I can create a template class that stores some values in a property and let me later call a method that call a function with this arg. Like this :
template <typename U> void g(U u) { cout << u << endl; }
template <typename U> class C {
public:
U u;
C(U u) { this->u = u; }
void m() { g(u); }
};
int main() {
C<double> c(5.5);
c.m();
}
But how to make the same with variadic templates ? I would like to write something like :
template <typename ... T> void f(T... a) { cout << "generik" << endl; }
template <typename ... T> class B {
public:
T... arg;
B(T... arg) {
this->arg = arg;
}
void m() { f(arg); }
};
int main() {
B<int,double> b(1,1.1);
b.m();
}
I know that it will not work because we cannot declare a member of unpacked parameter type.
I can do a pattern matching for some parameters of the list and then call the function if a given number of parameters is given, but I want to do it in a generic way. Is there an elegant way to do it ?
回答1:
http://ideone.com/OPl7Rz
#include <iostream>
#include <functional>
using namespace std;
template<typename... T>
void f(T... a)
{
std::initializer_list<int> {(std::cout<<a<<" ", 0)...};
}
template<typename... T>
class Defer
{
private:
std::function<void()> func;
public:
Defer(T... a) : func(std::bind(f<T...>, a...)) {}
void call() {func();}
};
int main()
{
Defer<int, float, int, const char*> d(1, 1.1, 2, "Hey");
d.call();
return 0;
}
回答2:
You may use something like the following:
template <typename... Ts> class B
{
public:
std::tuple<Ts...> t;
B(Ts... args)
: t(args...)
{
}
void m() { call_f(std::index_sequence_for<Ts>()); }
private:
template <std::size_t ... Is>
void call_f(std::index_sequence<Is...>)
{
f(std::get<Is>(t)...);
}
};
Note that std::index_sequence_for
(std::make_index_sequence
) and std::index_sequence
are C++14 but may be written in C++11.
Live example.
来源:https://stackoverflow.com/questions/27280629/variadic-template-class-to-make-a-deferred-call-to-a-variadic-template-function