How to tweak the variables, which a Lambda expression in Vala captures?

我是研究僧i 提交于 2019-12-02 09:49:06

Inside a lambda, no. The standard approach is this:

class Foo : Whatever {

  public Foo {
    unowned Foo unowned_this = this;
    this.bar_signal.connect(unowned_this.bar_handler);
  }
  private void bar_handler() {
    ...
  }
}

This doesn't capture a reference to this, but you also cannot capture any other variables.

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!