As per MSDN:
strtod
returns 0 if no conversion can be performed or an underflow occurs.
What if my string equals to zero (i.e., 0.0000)? How can I know if there is no error from the conversion?
OK, I use the following code to verify the idea:
char *Y = "XYZ";
double MyNum;
char *MyEndPtr;
int Err_Conversion = 0;
errno = 0; //reset
MyNum = strtod (Y, &MyEndPtr);
if ( (MyNum == 0) && (errno != 0) && (strcmp(Y, MyEndPtr) == 0) )
{ Err_Conversion = 1; }
I see that MyNum = 0, but never see the content of Y copied into MyEnPtr, or errno = 0 in this forced error. Any idea?
Use the str_end
parameter of the function. For example:
const char* str = "123junk";
char* str_end;
double d = strtod(str, &str_end);
// Here:
// d will be 123
// str_end will point to (str + 3) (the 'j')
// You can tell the string has some junk data if *str_end != '\0'
if (*str_end != '\0') {
printf("Found bad data '%s' at end of string\n", str_end);
}
If conversion totally fails, str
will equal str_end
:
const char* str = "junk";
char* str_end;
double d = strtod(str, &str_end);
// Here:
// d will be 0 (conversion failed)
// str_end will equal str
if (str == str_end) {
printf("The string doesn't start with a number!\n");
}
You can combine these two methods to make sure the string was (completely) successfully converted (that is, by checking str != str_end && *str_end == '\0'
)
The signature is (give or take restrict
keywords):
double strtod(const char *nptr, char **endptr);
If you pass a non-null pointer as the second argument, it will be returned with the value of nptr
if it could perform no conversion. If it found a genuine zero in the input string, then the value stored in *endptr
won't be nptr
.
char *end;
const char *data = "0.00000";
errno = 0;
double d = strtod(data, &end);
if (end != data)
...a conversion was performed...
else
...trouble...
You can also look at errno
, but you need to zero it before the call because no function in the standard C library or the POSIX library sets errno
to zero.
The standard says:
If the subject sequence is empty or does not have the expected form, no conversion is performed; the value of
nptr
is stored in the object pointed to byendptr
, provided thatendptr
is not a null pointer.Returns
The functions return the converted value, if any. If no conversion could be performed, zero is returned. If the correct value overflows and default rounding is in effect (7.12.1), plus or minus HUGE_VAL, HUGE_VALF, or HUGE_VALL is returned (according to the return type and sign of the value), and the value of the macro ERANGE is stored in
errno
. If the result underflows (7.12.1), the functions return a value whose magnitude is no greater than the smallest normalized positive number in the return type; whethererrno
acquires the value ERANGE is implementation-defined.
来源:https://stackoverflow.com/questions/27973759/return-value-of-strtod-if-string-equals-to-zero