问题
I have an extension to walk up the view controller chain (even through container views, which is very handy)
public extension UIViewController // go up to a certain class
{
public func above<T>(_ : T.Type)->(T)
{
var p:UIResponder = self
repeat { p = p.next! } while !(p is T)
return p as! T
}
}
(Aside, NB, Swift3 needs the "!" on p.next: unfortunately I'm not sure exactly why.)
So, say you have a view controller class "General", you can
self.above(General).clickedHamburgerMenuButton()
and it will find the first "General" above you. All fine but with Swift 3 you get this warning.......
Missing '.self' for reference to metatype of type 'General'
It seems to want this
self.above(General.self).clickedHamburgerMenuButton()
1) It seems ... dangerous ... to change General
to General.self
- in fact is it safe and is the meaning the same as General
in Swift <3 ?
2) in the extension
public func above<T>(_ : T.Type)->(T)
why is that a metatype? Did I "do something wrong" and make it ask for a metatype rather than just a type?
2) What the hell is a "metatype"? (I can't, really, find it explained as such anywhere.) That is to say, what can "general" possibly mean there other than "the class itself". (Not an instance, or a static instance, or anything else...)
回答1:
(Aside, NB, Swift3 needs the "!" on p.next: unfortunately I'm not sure exactly why.)
Because .next
returns an Optional, but p
is not optional. This will crash if you run out of responders.
1) It seems ... dangerous ... to change General to General.self - in fact is it safe and is the meaning the same as General in Swift <3 ?
I'm surprised that worked in earlier versions of Swift without the .self
, but yes, .self
is required in order to directly reference a metatype. Referencing metatypes is somewhat rare in Swift, and can lead to surprising behaviors if done unintentionally, so it requires an extra piece of syntax to say "yes, I really mean the type."
why is that a metatype? Did I "do something wrong" and make it ask for a metatype rather than just a type?
You did this correctly.
2) What the hell is a "metatype"?
The type of a type. An instance of a metatype is a type. Consider:
func f(x: Int)
To call this, you pass an instance of Int
. So similarly:
func f<T>(x: T.Type)
To call this, you pass an instance of the metatype T.Type
, which is a type.
Unrelated, but I would probably rethink this code along these lines. First, it is convenient to be able to treat the responder chain as a sequence. Here's one way to do that:
public extension UIResponder {
public func nextResponders() -> AnySequence<UIResponder> {
guard let first = next else { return AnySequence([]) }
return AnySequence(sequence(first: first, next: { $0.next }))
}
}
Then getting the next responder that matches a type is cleaner and clearer IMO (and works on any responder chain):
public extension UIResponder {
public func firstResponder<T: UIResponder>(ofType _: T.Type)-> T? {
return nextResponders()
.flatMap { $0 as? T }
.first
}
}
...
self.firstResponder(ofType: General.self)?.clickedHamburgerMenuButton()
来源:https://stackoverflow.com/questions/39835397/swift-3-is-the-self-in-a-metatype-issue-actually-correct