问题
I have to generate a list with two columns of day intervals for every month in a specific period. First column must be the first day of month and the second column the last day of month.
Example:
Start date: 2014-01-01
End date: 2014-06-30
The result should be in two columns:
1. 2014-01-01 | 2014-01-31
2. 2014-02-01 | 2014-02-28
3. 2014-03-01 | 2014-03-31
4. 2014-04-01 | 2014-04-30
5. 2014-05-01 | 2014-05-31
6. 2014-06-01 | 2014-06-30
I have two functions that get the first and last day from a date. I am trying to combine two series but with no luck.
select i::date
from generate_series(first_day('2014-01-01')
,first_day('2014-06-30'), '1 month'::interval) i
select i::date
from generate_series(last_day('2014-01-01')
,last_day('2014-06-30'), '1 month'::interval) i
The second function does not show the last day correctly when it is in the series.
回答1:
Based on this answer:
select d::date as start_date,(d + '1 month'::interval - '1 day'::interval )::date end_date
from generate_series('2014-01-01'::date, '2014-06-30'::date, '1 month'::interval) d
回答2:
You can even use a single interval expression:
SELECT d AS mon_first
,d + interval '1 month - 1 day' AS mon_last
FROM generate_series(date '2014-01-01'
,date '2014-06-30'
,interval '1 month') d
Details for interval input in the manual.
来源:https://stackoverflow.com/questions/21583877/create-list-with-first-and-last-day-of-month-for-given-period