问题
My table has two columns, id
and a
. Column id
contains a number, column a
contains an array of strings. I want to count the number of unique id for a given array, equality between arrays being defined as "same size, same string for each index".
When using GROUP BY a
, I get Grouping by expressions of type ARRAY is not allowed
. I can use something like GROUP BY ARRAY_TO_STRING(a, ",")
, but then the two arrays ["a,b"]
and ["a","b"]
are grouped together, and I lose the "real" value of my array (so if I want to use it later in another query, I have to split the string).
The values in this field array come from the user, so I can't assume that some character is simply never going to be there (and use it as a separator).
回答1:
Instead of GROUP BY ARRAY_TO_STRING(a, ",")
use GROUP BY TO_JSON_STRING(a)
so your query will look like below
#standardsql
SELECT
TO_JSON_STRING(a) arr,
COUNT(DISTINCT id) cnt
FROM `project.dataset.table`
GROUP BY arr
You can test it with dummy data like below
#standardsql
WITH `project.dataset.table` AS (
SELECT 1 id, ["a,b", "c"] a UNION ALL
SELECT 1, ["a","b,c"]
)
SELECT
TO_JSON_STRING(a) arr,
COUNT(DISTINCT id) cnt
FROM `project.dataset.table`
GROUP BY arr
with result as
Row arr cnt
1 ["a,b","c"] 1
2 ["a","b,c"] 1
Update based on @Ted's comment
#standardsql
SELECT
ANY_VALUE(a) a,
COUNT(DISTINCT id) cnt
FROM `project.dataset.table`
GROUP BY TO_JSON_STRING(a)
来源:https://stackoverflow.com/questions/48939402/bigquery-standard-sql-how-to-group-by-an-array-field