zipfile

Pandas. How to read Excel file from ZIP archive

只谈情不闲聊 提交于 2021-02-20 06:18:16
问题 I have .zip archive with filename.xlsx inside it and I want to parse Excel sheet line by line. How to proper pass filename into pandas.read_excel in this case? I tried: import zipfile import pandas myzip=zipfile.ZipFile(filename.zip) for fname in myzip.namelist(): with myzip.open(fname) as from_archive: with pandas.read_excel(from_archive) as fin: for line in fin: .... but it doesn't seem to work, and the result was: AttributeError: __exit__ 回答1: You can extract your zip-file into a variable

Pandas. How to read Excel file from ZIP archive

…衆ロ難τιáo~ 提交于 2021-02-20 06:13:27
问题 I have .zip archive with filename.xlsx inside it and I want to parse Excel sheet line by line. How to proper pass filename into pandas.read_excel in this case? I tried: import zipfile import pandas myzip=zipfile.ZipFile(filename.zip) for fname in myzip.namelist(): with myzip.open(fname) as from_archive: with pandas.read_excel(from_archive) as fin: for line in fin: .... but it doesn't seem to work, and the result was: AttributeError: __exit__ 回答1: You can extract your zip-file into a variable

Extract zip file and keeping top folder using python

那年仲夏 提交于 2021-02-11 12:32:29
问题 I have folder in like CW1234.zip and it has various folders and subfolders like below. So, CW1234.zip has CW_All folder which in turn has CW123 and CW234 folders and so on CW1234.zip CW_All CW123 xyz.pdf CW234 abc.doc and to extract I use this code: from zipfile import ZipFile with ZipFile(r'CW41234.zip', 'r') as zipObj: # Extract all the contents of zip file in current directory zipObj.extract() The only problem is the unzipped folder I get is from CW_All and all the subfolders and file.

Read Zip file content without extracting in java

早过忘川 提交于 2021-02-08 13:10:53
问题 I have byte[] zipFileAsByteArray This zip file has rootDir --| | --- Folder1 - first.txt | --- Folder2 - second.txt | --- PictureFolder - image.png What I need is to get two txt files and read them, without saving any files on disk. Just do it in memory. I tried something like this: ByteArrayInputStream bis = new ByteArrayInputStream(processZip); ZipInputStream zis = new ZipInputStream(bis); Also I will need to have separate method go get picture. Something like this: public byte[]image

Read Zip file content without extracting in java

五迷三道 提交于 2021-02-08 13:06:04
问题 I have byte[] zipFileAsByteArray This zip file has rootDir --| | --- Folder1 - first.txt | --- Folder2 - second.txt | --- PictureFolder - image.png What I need is to get two txt files and read them, without saving any files on disk. Just do it in memory. I tried something like this: ByteArrayInputStream bis = new ByteArrayInputStream(processZip); ZipInputStream zis = new ZipInputStream(bis); Also I will need to have separate method go get picture. Something like this: public byte[]image

Read Zip file content without extracting in java

故事扮演 提交于 2021-02-08 13:03:39
问题 I have byte[] zipFileAsByteArray This zip file has rootDir --| | --- Folder1 - first.txt | --- Folder2 - second.txt | --- PictureFolder - image.png What I need is to get two txt files and read them, without saving any files on disk. Just do it in memory. I tried something like this: ByteArrayInputStream bis = new ByteArrayInputStream(processZip); ZipInputStream zis = new ZipInputStream(bis); Also I will need to have separate method go get picture. Something like this: public byte[]image

python zipfile multiple files

倖福魔咒の 提交于 2021-02-08 09:45:07
问题 i am having problems with python and zipfile, namely: I can't add a second file to my zip. here is my code, if you need more, I'll be glad to provide it. def zipDir(fn_source, fn_destinationFolder): ''' fn_destinationFolder = folder to zip fn_source = destination path for the zip ''' fn_zipfileName = os.path.join(os.path.dirname(os.path.basename(fn_source)),fn_destinationFolder)+'.zip' with zipfile.ZipFile(fn_zipfileName, 'w') as fn_zipfile: for csvFile in os.listdir(fn_destinationFolder): #

How can I avoid: “ZipFile instance has no attribute '__exit__''” when extracting a zip file?

梦想的初衷 提交于 2021-02-07 14:47:50
问题 The code is: import sys execfile('test.py') In test.py I have: import zipfile with zipfile.ZipFile('test.jar', 'r') as z: z.extractall("C:\testfolder") This code produces: AttributeError ( ZipFile instance has no attribute '__exit__' ) # edited The code from "test.py" works when run from python idle. I am running python v2.7.10 回答1: I made my code on python 2.7 but when I put it on my server which use 2.6 I have this error : AttributeError: ZipFile instance has no attribute '__exit__' For

How can I avoid: “ZipFile instance has no attribute '__exit__''” when extracting a zip file?

二次信任 提交于 2021-02-07 14:45:52
问题 The code is: import sys execfile('test.py') In test.py I have: import zipfile with zipfile.ZipFile('test.jar', 'r') as z: z.extractall("C:\testfolder") This code produces: AttributeError ( ZipFile instance has no attribute '__exit__' ) # edited The code from "test.py" works when run from python idle. I am running python v2.7.10 回答1: I made my code on python 2.7 but when I put it on my server which use 2.6 I have this error : AttributeError: ZipFile instance has no attribute '__exit__' For