zipcode

Filter zipcodes by proximity in Django with the Spherical Law of Cosines

喜夏-厌秋 提交于 2019-11-28 04:25:49
I'm trying to handle proximity search for a basic store locater in Django. Rather than haul PostGIS around with my app just so I can use GeoDjango's distance filter, I'd like to use the Spherical Law of Cosines distance formula in a model query. I'd like all of the calculations to be done in the database in one query, for efficiency. An example MySQL query from The Internet implementing the Spherical Law of Cosines like this: SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) ) + sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance

mySQL select zipcodes within x km/miles within range of y

社会主义新天地 提交于 2019-11-27 22:42:41
问题 Note: Although I use a zipcode database with Dutch zipcodes, this question is country independent. I have a database with every zipcode in the Netherlands + its x and y coordinate (lat/long). I have for example zipcode: $baseZipCode = 1044; with the following coordinates: x coordinate = 4,808855 y coordinate = 52,406332 Now, I want to find all other zipcodes with $range from $baseZipCode . For example: SELECT zipcode FROM zipcodes WHERE ????? // Need help here The problem is that the earth is

mySQL select zipcodes within x km/miles within range of y

耗尽温柔 提交于 2019-11-27 19:06:52
问题 Note: Although I use a zipcode database with Dutch zipcodes, this question is country independent. I have a database with every zipcode in the Netherlands + its x and y coordinate (lat/long). I have for example zipcode: $baseZipCode = 1044; with the following coordinates: x coordinate = 4,808855 y coordinate = 52,406332 Now, I want to find all other zipcodes with $range from $baseZipCode . For example: SELECT zipcode FROM zipcodes WHERE ????? // Need help here The problem is that the earth is

How to get city name based on IP address in java?

醉酒当歌 提交于 2019-11-27 14:54:48
Is it possible to know the city name based on IP address in java? are you using jsp or what ? for city name over client side you can use google's API which will return you the geographical details of the user mapped with the IP. As google's documentation say you can get the following When populated, the google.loader.ClientLocation object is populated with the following metro-level granularity properties: * ClientLocation.latitude — supplies the low resolution latitude associated with the client's IP address * ClientLocation.longitude — supplies the low resolution longitude associated with the

MongoDB操作符

微笑、不失礼 提交于 2019-11-27 01:32:47
比较运算符 $eq 释义: 匹配等于 (=) 指定值的文档 示例: 查询age=20的文档: db.person.find( { age: { $eq: 20 } } ) 相当于: db.person.find( { age: 20 } ) $ne 释义:匹配不等于(≠)指定值的文档 $lt 释义:匹配小于(<)指定值的文档 $lte 释义: 匹配小于等于 (<=) 指定值的文档 $gt 释义:匹配大于 (>) 指定值的文档 $gte 释义:匹配大于等于 (>=) 指定值的文档 $in 释义:匹配数组中符合要求的值 示例: 查询该集合中字段qty的值与数组中的任意值相等的文档: db.inventory.find( { qty: { $in: [ 5, 15 ] } } ) $nin 释义:不匹配数组中得值 逻辑操作符 $or 释义:或 示例: 查询age<20或者address是beijing的文档: db.person.find( { $or: [ { age: { $lt: 20 } }, { address: "beijing" } ] } ) $and 释义:与 $not 释义:非 $nor 释义:一个条件都不满足 示例: 查询age既不等于20,sex也不是男的文档: db.person.find( { $nor: [ { age: 20 },{ sex: "男"} ]

Filter zipcodes by proximity in Django with the Spherical Law of Cosines

廉价感情. 提交于 2019-11-27 00:24:19
问题 I'm trying to handle proximity search for a basic store locater in Django. Rather than haul PostGIS around with my app just so I can use GeoDjango's distance filter, I'd like to use the Spherical Law of Cosines distance formula in a model query. I'd like all of the calculations to be done in the database in one query, for efficiency. An example MySQL query from The Internet implementing the Spherical Law of Cosines like this: SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat )

Mapping US zip code to time zone

末鹿安然 提交于 2019-11-26 21:46:46
When users register with our app, we are able to infer their zip code when we validate them against a national database. What would be the best way to determine a good potential guess of their time zone from this zip code? We are trying to minimize the amount of data we explicitly have to ask them for. They will be able to manually set the time zone later if our best guess is wrong. I realize zip codes won't help with figuring out the time zone outside the US, but in that case we'd have to manually ask anyway, and we deal predominantly with the US regardless. I've found a lot of zip code

ZipCode from location

霸气de小男生 提交于 2019-11-26 21:27:48
问题 Is there any way to get zip-code of the current user location from location or lat or long. If so how? 回答1: Yes you can...All you need to do is extract the http://maps.google.com/maps/geo?ll= latitude,longitude http://maps.google.com/maps/geo?ll=10.345561,123.896932 Or try experimenting this solutions.I can give you an idea. You can have a city right? WIth this json data, If you have a database(at maxmind.com) of the zipcode with this format CountryCode | City | ZipCode PH |Cebu |6000 Now

Calculate distance between Zip Codes… AND users.

♀尐吖头ヾ 提交于 2019-11-26 04:17:16
问题 This is more of a challenge question than something I urgently need, so don\'t spend all day on it guys. I built a dating site (long gone) back in 2000 or so, and one of the challenges was calculating the distance between users so we could present your \"matches\" within an X mile radius. To just state the problem, given the following database schema (roughly): USER TABLE UserId UserName ZipCode ZIPCODE TABLE ZipCode Latitude Longitude With USER and ZIPCODE being joined on USER.ZipCode =

What is the ultimate postal code and zip regex?

假装没事ソ 提交于 2019-11-26 03:20:46
问题 I\'m looking for the ultimate postal code and zip code regex. I\'m looking for something that will cover most (hopefully all) of the world. 回答1: There is none. Postal/zip codes around the world don't follow a common pattern. In some countries they are made up by numbers, in others they can be combinations of numbers an letters, some can contain spaces, others dots, the number of characters can vary from two to at least six... What you could do (theoretically) is create a seperate regex for