xsd

Validating XML against multiple XSD(stored as resources). Spring Boot

由 ↘锁芯ラ 提交于 2020-05-09 10:22:58
问题 I've spend a lot of time to validate XML against multiple XSD in Spring. Even when I give all XSD schemas to SchemaFactory it does not work because main schema can't see import schema declared in main XSD file. Even when I give this schemas as files it does not work, because Spring's resource files can't be resolved to absolute path . <xs:import namespace="http://test.com/types" schemaLocation="types.xsd"/> 回答1: 1. First we need this dependency which can parse xsd schemas: implementation("org

Validating XML against multiple XSD(stored as resources). Spring Boot

由 我的未来我决定 提交于 2020-05-09 10:22:08
问题 I've spend a lot of time to validate XML against multiple XSD in Spring. Even when I give all XSD schemas to SchemaFactory it does not work because main schema can't see import schema declared in main XSD file. Even when I give this schemas as files it does not work, because Spring's resource files can't be resolved to absolute path . <xs:import namespace="http://test.com/types" schemaLocation="types.xsd"/> 回答1: 1. First we need this dependency which can parse xsd schemas: implementation("org

how do we join in XPATH using version 1.0?

由 久未见 提交于 2020-04-18 06:10:13
问题 I'm trying to get the lN and the names of a person and the price of a car rental which is > 300 below is my XML example: <rent number="101111"> <car> <startDate>2018-02-08</startDate> <endDate>2018-03-05</endDate> <Location>Toranto</Location> <carType>BMW</carType> <transmissionType>Automatic</transmissionType> </car> <person> <licenseNumber> 02389749372 </licenseNumber> <name>Alexa Steve</name> <dob>1999-03-01</dob> <phone> <type>Home</type> <number>44 010 1111 4567</number> </phone> <email>

How do we get the Longest Booking in XPATH 1.0?

由 夙愿已清 提交于 2020-04-17 20:20:25
问题 How can I get the name of the person who has the longest Booking using the attribute StartDate and EndDate belwo i menioned the xml dummy data i have like 12 diffrent datas and more people , the version i am using for xpath is 1.0 <rent number="101111"> <car> <startDate>2018-02-08</startDate> <endDate>2018-03-05</endDate> <Location>Toranto</Location> <carType>BMW</carType> <transmissionType>Automatic</transmissionType> </car> <person> <licenseNumber> 02389749372 </licenseNumber> <name>Alexa

How do we get the Longest Booking in XPATH 1.0?

由 瘦欲@ 提交于 2020-04-17 20:17:45
问题 How can I get the name of the person who has the longest Booking using the attribute StartDate and EndDate belwo i menioned the xml dummy data i have like 12 diffrent datas and more people , the version i am using for xpath is 1.0 <rent number="101111"> <car> <startDate>2018-02-08</startDate> <endDate>2018-03-05</endDate> <Location>Toranto</Location> <carType>BMW</carType> <transmissionType>Automatic</transmissionType> </car> <person> <licenseNumber> 02389749372 </licenseNumber> <name>Alexa

How do we get the Longest Booking in XPATH 1.0?

由 。_饼干妹妹 提交于 2020-04-17 20:17:25
问题 How can I get the name of the person who has the longest Booking using the attribute StartDate and EndDate belwo i menioned the xml dummy data i have like 12 diffrent datas and more people , the version i am using for xpath is 1.0 <rent number="101111"> <car> <startDate>2018-02-08</startDate> <endDate>2018-03-05</endDate> <Location>Toranto</Location> <carType>BMW</carType> <transmissionType>Automatic</transmissionType> </car> <person> <licenseNumber> 02389749372 </licenseNumber> <name>Alexa

How do we get the Longest Booking in XPATH 1.0?

由 为君一笑 提交于 2020-04-17 20:16:27
问题 How can I get the name of the person who has the longest Booking using the attribute StartDate and EndDate belwo i menioned the xml dummy data i have like 12 diffrent datas and more people , the version i am using for xpath is 1.0 <rent number="101111"> <car> <startDate>2018-02-08</startDate> <endDate>2018-03-05</endDate> <Location>Toranto</Location> <carType>BMW</carType> <transmissionType>Automatic</transmissionType> </car> <person> <licenseNumber> 02389749372 </licenseNumber> <name>Alexa

Python create xml from xsd

由 两盒软妹~` 提交于 2020-04-12 09:41:32
问题 I am new with python and need to implement an interface to an accounting tool. I received some XSD Files which describes the interface. What is the easiest way to generate the XML according to the XSD? Is there any module I can use? Do I have to create the XML all by myself and I can use the XSD just to verify it? How do I best proceed? 回答1: I think, generateDS is the solution to your problem. Starting from chapter 5, the command python generateDS.py -o people.py -s peoplesubs.py people.xsd

缘起 Dubbo ，讲讲 Spring XML Schema 扩展机制

由 情到浓时终转凉″ 提交于 2020-04-06 03:42:48
背景 在 Dubbo 中，可以使用 XML 配置相关信息，也可以用来引入服务或者导出服务。配置完成，启动工程，Spring 会读取配置文件，生成注入 相关 Bean。那 Dubbo 如何实现自定义 XML 被 Spring 加载读取？ Spring XML Schema 扩展机制。从 Spring 2.0 开始，Spring 开始提供了一种基于 XML Schema 格式扩展机制，用于定义和配置 bean。 Spring XML Schema 扩展机制 实现 Spring XML Schema 扩展，其实非常简单，只需要完成下面四步。 创建 XML Schema 文件，由于该文件后缀名为 xsd，下面称为 XSD 文件。 编写实现一个或多个 BeanDefinitionParser 。 编写 NamespaceHandler 实现类。 注册 NamespaceHandler 以及 XSD 文件。 我们按照以上步骤,最终完整 Spring 解析如下配置。 <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:demo=

Spring框架中的aop操作之一 及aspectjweaver.jar与aopalliance-1.0.jar下载地址 包含beans 注解context 和aop的约束

由 旧时模样 提交于 2020-03-30 21:13:16
(aspect oriented programming面向切面编程) 首先在原有的jar包： 需Spring压缩包中的四个核心JAR包 beans 、context、core 和expression 下载地址： https://pan.baidu.com/s/1qXLHzAW 以及日志jar包 commons-logging 和log4j 下载地址： https://pan.baidu.com/s/1mimTW5i 再增加一个 spring-aop-5.0.1.RELEASE.jar (用于注解，在Spring-framework库中包含） 再增加 spring-aspects-5.0.1.RELEASE.jar (在Spring-framework库中包含） aspectjweaver-1.8.12.jar (官方下载地址 http://mvnrepository.com/artifact/org.aspectj/aspectjweaver） spring收购的aspectj的一部分包只关于weaver的 aopalliance-1.0.jar (官方下载地址 http://mvnrepository.com/artifact/aopalliance/aopalliance/1.0） 上边是aop联盟的包 然后在 Spring
订阅 xsd